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Sunny_sXe [5.5K]
3 years ago
8

Help meeeeee plzz Think about how to use the interactive tool to form an expression equivalent to –x + ( –3x) + 12 – 9. An equiv

alent expression is______ + 3.
-4x
-2x
2x
4x
Mathematics
2 answers:
Stolb23 [73]3 years ago
8 0
The answer is -4x+3.......
elena55 [62]3 years ago
3 0

Answer:

Expression equivalent to

-x+(-3x)+12-9

An equivalent expression is -4x+3

Step-by-step explanation:

We have the expression:

-x+(-3x)+12-9

We need to simplify this expression:

-x+(-3x)+12-9\\-x-3x+12-9\\-4x+3

An equivalent expression is -4x+3

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In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

6 0
3 years ago
Cushing's disease is characterized by muscular weakness due to adrenal or pituitary dysfunction. To provide effective treatment,
Katyanochek1 [597]

Answer:

Since the calculated value of t =-0.427 does not  fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the  age of onset of symptoms and age of diagnosis is  25 months  .

Step-by-step explanation:

The given data is

Difference d= -24 -12 -55 -15 -30 -60 -14 -21 -48 -12 -25 -53 -61 -69 -80

∑ d= -579

 ∑d²= 29871

1) Let the hypotheses be

H0: ud= 25 against the claim    Ha: ud ≠25

H0 : mean difference in the  age of onset of symptoms and age of diagnosis is  25 months  .

Ha:   mean difference in the  age of onset of symptoms and age of diagnosis is not 25 months.

 

2) The degrees of freedom = n-1= 15-1= 14

3) The significance level is 0.05

4) The test statistic is

t= d`/sd/√n

The critical region is ║t║≤ t (0.025,14) = ±2.145

d`= ∑di/n= -579/15= -38.6

Sd= 23.178  (using calculators)

Therefore

t= d`/ sd/√n

t= -38.6/ 23.178√15

t= -1.655/3.872= -0.427

5) Since the calculated value of t =-0.427 does not  fall in the critical region so we accept H0 and conclude that there is enough evidence to show that mean difference in the  age of onset of symptoms and age of diagnosis is  25 months  .

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3 years ago
An expression is a numeric characteristic of a subject, sample, or population. True or False?
Rainbow [258]
The statement above is TRUE.
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3 years ago
Which measures is equivalent to 126 in.?
Alona [7]
Answer is b my friend hope it helps if ya need me to explain I can for u:3
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3 years ago
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A line with a slope of 5 passes through the point (0,0). What is its equation in slope-intercept form?
Masja [62]

Answer:

y=5x or y=5x+0

Step-by-step explanation:

there is a slope of 5 and it has no setoff

5 0
3 years ago
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