All categories

2 years ago

What value of x makes this statement true? 3x=2x+12 A) 2 B) 5 C) 6 D) 12

Mathematics

1 answer:

vekshin12 years ago

4 0

Answer:

The value of x = 12, makes the statement $3x=2x+12$ true

Option D is correct option.

Step-by-step explanation:

What value of x makes this statement true?

$3x=2x+12$

We need to solve the equation to find value of x

$3x=2x+12$

Subtract 2x on both sides

$3x-2x=2x+12-2x\\x=12$

So, the value of x is: x=12

So, The value of x = 12, makes the statement $3x=2x+12$ true

Option D is correct option.

You might be interested in

at ralphs fruit stand 1/2 pound of grapes is 90 cents you ant to buy 5 pounds of grapes, how much will they cost? PART A: what a

Karolina [17]

HY OLA SUN TEFONO ME QVLOE AHRAC JU PSTICIORQ ME QUITASTUE MIS UNTPOS PER LAO RESPUSTA ES QU HEEEAYFRUS RALPH LIBRTA UVS AA A 8NTAVOS0 CE

5 0

3 years ago

Julia is allowed to watch no more than 5 hours of television a week. So far this week, she has watched 1.5 hours. Write and solv

Leona [35]

The inequality is used to solve how many hours of television Julia can still watch this week is $x + 1.5 \leq 5$

The remaining hours of TV Julia can watch this week can be expressed is 3.5 hours

<h3><u>Solution:</u></h3>

Given that Julia is allowed to watch no more than 5 hours of television a week

So far this week, she has watched 1.5 hours

To find: number of hours Julia can still watch this week

<em>Let "x" be the number of hours Julia can still watch television this week</em>

"no more than 5" means less than or equal to 5 ( ≤ 5 )

Juila has already watched 1.5 hours. So we can add 1.5 hours and number of hours Julia can still watch television this week which is less than or equal to 5 hours

number of hours Julia can still watch television this week + already watched ≤ Total hours Juila can watch

$x + 1.5 \leq5$

Thus the above inequality is used to solve how many hours of television Julia can still watch this week.

Solving the inequality,

$x + 1.5 \leq5\\\\x \leq 5 - 1.5\\\\x \leq 3.5$

Thus Julia still can watch Television for 3.5 hours

5 0

2 years ago

Sole the question l2l

Feliz [49]

what question theres none

4 0

2 years ago

Since sq root 3 times sq root 3 is rational, the product of any two irrational numbers is rational. Which of the following best

Anna71 [15]

What are the rest of the answer choices?

5 0

3 years ago

Find the indefinite integral. (Use C for the constant of integration.)

mart [117]

Answer:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

tep-by-step explanation:

In order to find the integral:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx$

we can do the following substitution:

Let's call

$u=(x^3-x^2+x)$

Then

$du = (3x^2-2x+1) dx$

which allows us to do convert the original integral into a much simpler one of easy solution:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C$

Therefore, our integral written in terms of "x" would be:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

7 0

2 years ago