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Morgarella [4.7K]
3 years ago
6

Diane received 300 votes in the election for student council president. That was 60% of the students who voted election. How man

y students voted in the election?
Mathematics
2 answers:
VikaD [51]3 years ago
8 0

Answer:

  500

Step-by-step explanation:

The problem statement tells you ...

  300 = 0.60×voters

Dividing by the coefficient of the variable gives ...

  300/0.60 = voters = 500

500 students voted in the election.

Tatiana [17]3 years ago
3 0

Answer:

500

Step-by-step explanation:

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Answer:

Hi there!

Your answer is:

B. 1.5

Step-by-step explanation:

The square root of 2.25 = 1.5

Check your work!

1.5×1.5 = 2.25!!✓

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2 years ago
8. Crayons are packed in boxes of 8 and 10 pieces. What is the smallest number of crayons
Ede4ka [16]

Step-by-step explanation:

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2 years ago
45 POINTS!! Please help me solve this Table I’m having a hard time this is my last chance to pass!
Anettt [7]

Solution:

<u>Given function:</u>

  • f(x) = x - 1

<u>Solution (x = -2):</u>

  • f(x) = x - 1
  • => -2 - 1
  • => -3

<u>Solution (x = 0):</u>

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<u>Solution (x = 2):</u>

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8 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
tangare [24]

Answer:

<h3>The given expression can be written in the form q(x)+\frac{r(x)}{b(x)} as (2x^2-x+3)+\frac{0}{x-3} where  q(x)=2x^2-x+3 , r(x)=0 and b(x)=x-3</h3>

Step-by-step explanation:

Given rational expression is \frac{2x^3-7x^2+6x-9}{x-3}

<h3>To rewrite the given rational expression in the given form  and match their correct expressions:</h3>

Rewrite the given rational expression \frac{2x^3-7x^2+6x-9}{x-3} in the form of q(x)+\frac{r(x)}{b(x)} where q(x) is the quotient, r(x) is the remainder and b(x) is the divisor.

<h3>Now solve the given expression by using Synthetic division, we get</h3>

Since x-3 is a factor for 2x^3-7x^2+6x-9

<h3>Therefore b(x)=x-3</h3>

3_|   2     -7     6     -9

       0      6    -3      9

   ------------------------------------

      2      -1       3      0

  ------------------------------------

Therefore we have quadratic equation 2x^2-x+3=0

<h3>q(x)=2x^2-x+3</h3><h3>Remainder is 0</h3><h3>Therefore r(x)=0</h3>

Therefore we can write in the form as (2x^2-x+3)+\frac{0}{x-3}

It is in the form of q(x)+\frac{r(x)}{b(x)}

<h3>Therefore the given expression can be written in the form q(x)+\frac{r(x)}{b(x)} as (2x^2-x+3)+\frac{0}{x-3} where  q(x)=2x^2-x+3 , r(x)=0 and b(x)=x-3</h3>

3 0
2 years ago
Read 2 more answers
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