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svp [43]
3 years ago
10

Two trains leave Raleigh at the same time one traveling north and the other south the first train travels at 50 miles per hour a

nd the second at 60 miles per hour in how many hours will the trains be in 275 miles apart
Mathematics
1 answer:
Elis [28]3 years ago
4 0

Answer:

<h2>2.5 hours</h2>

Step-by-step explanation:

Step one:

given data

for train one

speed= 50miles per hour

for train two

speed= 60miles per hour

the total distance between both trains=275miles

Step two:

the expression for speed= distance/time

so that, distance= speed*time

let the time be t

we are going to combine both distances

train one distance =50t

train two distance =60t

Hence total distance

50t+60t=275

110t=1=275

t=275/110

t=2.5 hours

<u>It will take 2.5 hours</u>

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Find each sum.
Greeley [361]

Answer:

Sum is - 5n² -8n + 4.

Step-by-step explanation:

Given : (3n² – 5n + 6) + (–8n²– 3n – 2) .

To find : Sum .

Solution : We have (3n² – 5n + 6) + (–8n²– 3n – 2) .

Combine like terms :

(3n² - 8n²– 5n - 3n + 6 - 2).

- 5n² -8n + 4.

Therefore, Sum is - 5n² -8n + 4.

8 0
3 years ago
Read 2 more answers
How to describe partial products yo 4th grader
erastova [34]

To describe partial products in a "laymans" term, you'd have to set up an problem with the 4th grader.

Set it up in a big format and even make a game out of it with tiles on the floor.

Explain to the 4th grader that the number on the bottom will be multiplied by each number separately and then eventually added. For more than one digit multiplication problems, they add a "0" for each number they are on. Example: One zero after the first number is multiplied. Two zero's after the second number is multiplied, etc...

Then, you just add like normal.


I have actually used the tile method to help my 4th grader learn how to do partial products.

I suggest making BIG 8x10 numbers. Then, tape them (gently) on the floor. Have the 4th grader stand on the first number they'd be multiplying. Example:

12 x 6

The student would stand on the number 6. You then ask them to jump (or hop-just be careful of slippery surfaces) on the number they have to multiply with next; which would be the 2. You'd ask them, what is "6 x 2?". They should reply with 12.

Next, have another set of smaller numbers where they can come back and place the numbers. 2 would go on the bottom and they hold the 1 so they can remember they need to add it to the next multiplication number.

So, now you'd have them stand on the number 6 again. Ask where they have to multiply again. They should move to the 1. Ask what is "6x1". Then answer should be 6. Then remind them they are holding a number and what they should do with it. The answer should be "add it to the answer of the multiplication". So, it should be 6+1=7. Then, they'd place the number 7 at the bottom of the problem.

Once they figure it out with single digits, move onto double digits at the bottom and work up from there.  

This way, they are having to use BIG movements and will eventually gain muscle memory on which directions and how to multiple correctly.


GOOD LUCK!

3 0
3 years ago
The three medals earned in the Olympics are the gold, silver, and bronze medals. In the 2014 Winter Olympics, the United States
marta [7]

Answer:

Let x be the number of silver medals.

As there were two more gold medals than silver ones, gold medals are x+2

We also know that the number of bronze medals was 4 less than the sum of gold and silver, so if there are x + 2 of gold and x of silver, there are x+x+2-4 of bronze.

Now, we can do an equation, as we know there were a total of 28 medals:

x + x + 2 + x + x + 2 - 4 = 28

And we isolate x:

4x = 28

x = 28/4 = 7

There were 7 silver medals, so there were 9 gold ones (7-2) and 12 of bronze (9+7-4).

4 0
3 years ago
An article reported on the results of an experiment in which half of the individuals in a group of 66 postmenopausal overweight
kicyunya [14]

Answer:

We conclude that the true average weight loss for the vegan diet exceeds that for the control diet by more than 1 kg.

Step-by-step explanation:

We are given that an article reported on the results of an experiment in which half of the individuals in a group of 66 postmenopausal overweight women were randomly assigned to a particular vegan diet, and the other half received a diet based on National Cholesterol Education Program guidelines.

The sample mean decrease in body weight for those on the vegan diet was 6 kg, and the sample SD was 3.2, whereas, for those on the control diet, the sample mean weight loss and standard deviation were 3.8 and 2.4, respectively.

Let = true average weight loss for the vegan diet.

\mu_2 = <em>true average weight loss for the control diet.</em>

So, Null Hypothesis, : 1 kg      {means that the true average weight loss for the vegan diet exceeds that for the control diet by less than or equal to 1 kg}

Alternate Hypothesis, : > 1 kg      {means that the true average weight loss for the vegan diet exceeds that for the control diet by more than 1 kg}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about population standard deviations;

                            T.S.  =  \frac{(\bar X_1-\barX_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }   ~    t__n_1_+_n_2_-_2

where, = sample mean weight loss for the vegan diet = 6 kg

 = sample mean weight loss for the control diet = 3.8 kg

 = sample standard deviation weight loss for the vegan diet = 3.2 kg

 = sample standard deviation weight loss for the control diet = 2.4 kg

n_1  = sample of vegan diet women = 33

n_2 = sample of control diet women = 33

Also, s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  = \sqrt{\frac{(33-1)\times 3.2^{2}+(33-1)\times 2.4^{2} }{33+33-2} } = 2.83

So, <u><em>the test statistics</em></u> =  \frac{(6-3.8)-(1)}{2.83 \times \sqrt{\frac{1}{33}+\frac{1}{33}  } }  ~  t_6_4

                                    =  1.722  

The value of t-test statistics is 1.722.

<u>Also, the P-value of the test statistics is given by;</u>

               P-value = P(t_6_4 > 1.722) = 0.0461 or 4.61%

Since the P-value of our test statistics is less than the level of significance as 0.0461 < 0.05, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the true average weight loss for the vegan diet exceeds that for the control diet by more than 1 kg.

3 0
3 years ago
Name two coordinates that are on the line: <img src="https://tex.z-dn.net/?f=y%20%3D%2012" id="TexFormula1" title="y = 12" alt="
Eva8 [605]

Answer:

(1,12) and (2,12).

(- 5,1) and (- 5, 2).

Step-by-step explanation:

y = 12 is a line that is parallel to the x-axis and at a constant distance of 12 units above the x-axis. Therefore, the points on the line will have any x-coordinate but have a constant y-coordinate i.e. 12.

Therefore, the two points on the line y = 12 can be (1,12) and (2,12).  

x = - 5 is a line that is parallel to the y-axis and at a constant distance of 5 units left of the y-axis. Therefore, the points on the line will have any y-coordinate but have a constant x-coordinate i.e. - 5.

Therefore, the two points on the line x = - 5 can be (- 5,1) and (- 5, 2).  (Answer)

3 0
3 years ago
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