Answer:
x = $3, or x = $11
Step-by-step explanation:
The equation given is
where
- P(x) is the profit, and
- x is the app price
<u>We want app prices (x's) when profit (P(x)) is 0, so plugging in into the equation:</u>

<em>It means (x-3) = 0 OR (x-11) = 0</em>
So, x = 3, or 11
Answer:
Step-by-step explanation:
Givem the profit function
p(x) = −2000x2 + 18000x − 15000
We are to generate the price range that will generate a monthly profit of at least $25,000
Substitute into the function we have;
25000 = −2000x2 + 18000x − 15000
Divide through by 1000
25 = -2x²+18x-15
Rearrange
-2x²+18x-15-25 = 0
2x²-18x+40 = 0
Divide through by 2
x²-9x+20 = 0
Factorize
x²-5x-4x+20 = 0
x(x-5)-4(x-5) = 0
x-4 = 0 and x-5 = 0
x = 4 and x = 5
Hence the price range that will generate a monthly profit of at least $25,000 is between $4 and $5 inclusive
Answer:
-15r
Step-by-step explanation:
Answer:
Since it has smaller absolute and relative errors, 355/113 is a better aproximation for
than 22/7
Step-by-step explanation:
The formula for the absolute error is:
Absolute error = |Actual Value - Measured Value|
The formula for the relative error is:
Relative error = |Absolute error/Actual value|
I am going to consider the actual value of
as 3.14159265359.
In the case of 22/7:
22/7 = 3.14285714286.
Absolute error = |3.14159265359 - 3.14285714286| = 0.00126448927
Relative error = 0.00126448927/3.14159265359 = 0.00040249943 = 0.04%
In the case of 355/113
355/113 = 3.14159292035
Absolute error = |3.14159265359 - 3.14159292035| = 0.00000026676
Relative error = 0.00000026676/3.14159265359 = 0.000000085 = 0.0000085%
Since it has smaller absolute and relative errors, 355/113 is a better aproximation for
than 22/7