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seropon [69]
2 years ago
15

Given f(x)=2x^2-3 and g(x) = x+4 What is (fg)(x)?

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
4 0

Answer: f(g(x))=2x^2+16x+29

Step-by-step explanation:

f(x)=2x^2-3\\g(x)=x+4

f of g of x means "function f, replace x by the value of g of x"

f(g(x))=2x^2-3\\f(g(x))=2(x+4)^2-3\\f(g(x))=2(x^2+8x+16)-3\\f(g(x))=2x^2+16x+32-3\\f(g(x))=2x^2+16x+29

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Does anyone know the answer???
irakobra [83]

Answer:

<h2>3,600 m²</h2>

Step-by-step explanation:

The formula of a surface area of a sphere:

SA=4\pi R^2

<em>R</em><em> - radius</em>

<em />

We have <em>R = 30m</em>.

Substitute:

SA=4\pi(30^2)=4\pi(900)=3600\pi\ m^2

5 0
3 years ago
Three balls are packaged in a cylindrical container as shown below. The balls just touch the top, bottom, and sides of the cylin
lianna [129]
We know the following:
Cylinder volume: V₁ = π r² h
Ball (sphere) volume:V₂ = \frac{4}{3} π r³
where:
V - volume
r - radius of base of cylinder and diameter of ball
h - height of cylinder.

R = 13 cm ⇒ r = 13 ÷ 2 = 6.5
π = 3.14

a) Since balls touch all sides of cylinder (as shown in image), it can be concluded that height of cylinder is equal to sum of diameters of 3 balls and that radius of base of cylinder is equal to radius of ball:
h = 3 × r = 3 × 13 cm = 39 cm
r = 6.5 cm
So,
V₁ = <span>π r² h
</span><span>V₁ = </span>3.14 × (6.5 cm)² × 39 cm
V₁ = 5,173.9 cm³

b. The total volume of three balls is the sum of volumes of each ball:
Vₐ = 3 × <span>V₂ 
</span>Vₐ = 3 × <span>\frac{4}{3} π r³
</span>Vₐ = 3 × \frac{4}{3} 3.14<span> (6.5 cm)³</span>
Vₐ = 3,449.3 cm³

c. Percentage of the volume of the container occupied by three balls ould be expressed as ratio of volume of three balls and volume of cylinder:
V = \frac{ V_{1}}{ V_{a} } ×100 
V = \frac{3,449.3}{5,173.9} ×100
V = 0.6666 ×100
V = 66.66%
4 0
2 years ago
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adelina 88 [10]
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4 0
2 years ago
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My name is Ann [436]

Answer:

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Step-by-step explanation:

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