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seropon [69]
3 years ago
15

Given f(x)=2x^2-3 and g(x) = x+4 What is (fg)(x)?

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer: f(g(x))=2x^2+16x+29

Step-by-step explanation:

f(x)=2x^2-3\\g(x)=x+4

f of g of x means "function f, replace x by the value of g of x"

f(g(x))=2x^2-3\\f(g(x))=2(x+4)^2-3\\f(g(x))=2(x^2+8x+16)-3\\f(g(x))=2x^2+16x+32-3\\f(g(x))=2x^2+16x+29

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You observe the heights of two plants for an experiment. Plant A has a height of 8 centimeters and grows 1 centimeter each week.
saveliy_v [14]

Answer:

69

Step-by-step explanation:

8 0
3 years ago
Help with this question ??
NNADVOKAT [17]

Answer: 12 tables minimum, 15 max.

Step-by-step explanation:

If you substitute 14 in an inequality

200c + 500t >= 8800

200(14) + 500t and solve for t, you get t must be at least 12.

C +T cannot exceed 29

So figure 14 +12 =26 so they could sell up to 15 tables and not go over 29.

You will have to enter the t values 12,13,14,15

5 0
3 years ago
Samuel buys office supplies for his home buissness
Reil [10]

Answer:

What supplies?

Step-by-step explanation:

6 0
2 years ago
The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

   ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

                    the probability that he will be more than 76 inches tall.

              (b) If two men are chosen at random from the population, find

                    the probability that

                    (i) both of them will be more than 76 inches tall;

                    (ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{S.D}) > \frac{( 76- mean)}{S.D})

                 = P(Z >  \frac{( 76- mean)}{S.D})

                 = P(Z > \frac{76 - 69.7}{2.8})

                 = P(Z > 2.25)

                 = 1 - P(Z  ≤ 2.25)

                 = 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

                                                                           = 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

\frac{S.D}{\sqrt{N} } = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

                 = P( \frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } })) > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } })

                 = P(Z > \frac{( 76- 69.7)}{1.979899 }))

                 = P(Z > 3.182)

                 = 1 - P(Z ≤ 3.182)

                 = 0.0007

⇒P(Y > 76) = 0.0007

6 0
3 years ago
Which function has a vertex at the origin?
aksik [14]

Answer:

f(x)=-x2

Step-by-step explanation:

I believe the first one has a vertex at (-4, 0), the second at (4, 0), the third at (4, -4). The only remaining answer is the last one.

8 0
3 years ago
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