Answer:
NO
Step-by-step explanation:
The changeability of a sampling distribution is measured by its variance or its standard deviation. The changeability of a sampling distribution depends on three factors:
- N: The number of observations in the population.
- n: The number of observations in the sample.
- The way that the random sample is chosen.
We know the following about the sampling distribution of the mean. The mean of the sampling distribution (μ_x) is equal to the mean of the population (μ). And the standard error of the sampling distribution (σ_x) is determined by the standard deviation of the population (σ), the population size (N), and the sample size (n). That is
μ_x=p
σ_x== [ σ / sqrt(n) ] * sqrt[ (N - n ) / (N - 1) ]
In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction. When the population size is very large relative to the sample size, the finite population correction is approximately equal to one; and the standard error formula can be approximated by:
σ_x = σ / sqrt(n).
Answer- A-16
Because when doing completing the square, you divide the coefficient of x by 2, which is 4, and the square it which is 16
Answer:
476.37
Step-by-step explanation:
$12.98/hr at KF (Key Food)
$x/36.7, so look at it fractionally.
36.7x12.98
This wil be 476.366
Rounding to the nearest hundredth is 2 decimal places (tenths, hundredths).
476.366 will be 476.37
Answer:
(3•22g4h5)
Step-by-step explanation:
Step 1: ((3gh2 • 4) • g3) • h3
Step 2: ((3•22gh2) • g3) • h3
Step 3: 3.1 h2 multiplied by h3 = h(2 + 3) = h5
Final answer: (3•22g4h5)
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<span>rate = dist/time so 406/7=58 hope this help
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