Answer:
She rewrote the problem without parentheses: x3+ 2x2 - x + x3 – 2x2 +6
Step-by-step explanation:
It looks like she didn't fully distribute the -
(x3 + 2x2 - x)-(-x3 + 2x2 + 6) :Original
x3+ 2x2 - x + x3 – 2x2 +6 :Changed
~
(x3 + 2x2 - x)-(-x3 + 2x2 + 6)
x3 + 2x2 - x + x3 - 2x2 - 6
x3 + x3 + 2x2 - 2x2 -x - 6
2x3-x-6
I hope this helps ^-^
Let the smaller number be x and the larger number be y.
We can calculate this by using simultaneous equation, aka listing 2 equations out.
From given,
X + y = 43
Let this be equation no. 1
X + 19 = y
Let this number be equation 2.
We can do simultaneous equations either by substitute method or elimination. In this case I'm using substitute.
We can already obtain the value of y (in terms of x) in euqation no. 2, so all we gonna do is to put y into equation 1.
X + x + 19 = 43
Solve this by algebra.
2x = 43 - 19
X = 12
Now we know the exact value of x
Now substitute x = 12 into equation no. 2
12 + 19 = y
Y = 31
So the answer is 12 and 31
Answer:
378
Step-by-step explanation:
9*6=54 then 54/2=27. fnally 27*14=378
1. It is the product of a square, meaning it can be simplified to (x+10)(x+10) or (x+10)^2
Answer:
can u write the question
Step-by-step explanation:
pls the I will answer it
