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PtichkaEL [24]
3 years ago
11

What effect has urbanization had on air pollution in the United States and around the world?

Biology
1 answer:
prohojiy [21]3 years ago
6 0

Answer:

Providing less mass transportation leads to less air pollution.

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Which best describes the nature of cellular respiration?
ivolga24 [154]
Cellular respiration is a set of metabolic reactions and processes that take place in the cells of organisms to convert biochemical energy from nutrients into adenosine triphosphate (ATP), and then release waste products.

Hope this helps...
3 0
3 years ago
Read 2 more answers
The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61
erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately<u> 6890 years.</u>

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

<u>Available data</u>:

  • The half-life of C14 is 5730 years
  • Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g
  • C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5730 years
  • T₀ = Time when the organism was alive
  • T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

<u>λ = 0.0001209</u>

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 =<u> - 0.833</u>

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ =  6889.99 ≅ <u>6890 years</u>

The bones are approximately<u> 6890 years.</u>

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

#SPJ1

6 0
2 years ago
A 55-year-old male was admitted to the hospital with heart failure. he complains of increasing shortness of breath on exertion,
Kipish [7]
This patient both has left-sided heart failure and right-sided heart failure. In left-sided heart failure, this patient exhibits increasing shortness of breath on exertion as well as three pillow orthopnea which indicates pulmonary congestion. This is because of pooling of blood in the pulmonary circulation. Bipedal edema, in this patient is a grade 2 bipedal edema, reflect right-sided heart failure as there is pooling of blood in the systemic circulation, causing transudation in the most dependent areas of the body. 
7 0
3 years ago
Paperclip floating on water - What water property is being shown
schepotkina [342]

Answer:

The water property being shown is surface tension

Explanation:

Due to the surface tension, small objects will "float" on the surface of a fluid, as long as the object cannot break through and separate the top layer of water molecules. When an object is on the surface of the fluid, the surface under tension will behave like an elastic membrane.

6 0
3 years ago
Myristoyl-CoA is a saturated fatty acid with 14 carbons attached to coenzyme A. How many molecules of ATP would be generated fro
sladkih [1.3K]

Answer:

Total ATP molecules produced = 94 molecules of ATP

Explanation:

Myristoyl-CoA, is a saturated fatty acid with 14 carbons which has been activated for oxidation by attachment to coenzyme A. When it has undergone complete oxidation, it will yield 7 acetyl-CoA molecules and 6 FADH₂ and 6 NADH molecules each.

Each of the 7 acetyl-CoA molecules obtained from its initial oxidation enters into the citric acid cycle and is completely oxidized to yield further ATP and  FADH₂ and NADH molecules.

The overall yield of ATP from the various enzymatic steps is shown below:

Acyl-CoA dehydrodenase = 6 FADH₂

β-Hydroxyacyl-CoA dehydrogenase = 6 NADH

Isocitrate dehydrogenase = 7 NADH

α-Ketoglutarate dehydrogenase = 7 NADH  

Succinyl-CoA synthase = 7 ATP (from substrate-level phosphorylation)  

Succinate dehydrogenase = 7 FADH₂

Malate dehydrogenase = 7 NADH

Note: 1 FADH2 molecule yields 1.5 ATP; 1 NADH molecule yields 2.5 ATP molecules. Therefore,

Total ATP  from FADH₂ molecules = 13 * 1.5 = 19.5  

Total NADH molecules = 27 * 2.5 = 67.5

Total ATP molecules produced = 19.5 + 67.5 + 7  = 94

Total ATP molecules produced = 94 molecules of ATP

4 0
3 years ago
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