i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X

<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
I hope this helps you
x= 3
f (3)= 3.3^2-2= 27-2=25
g (3)= 3+7=10
f (3)-g (3)= 25-10= 15
Answer:
A=216
Step-by-step explanation:
16·27 then you divide by 2
25 ounces of guacamole are still expected to be available from batch.
Step-by-step explanation:
Given,
Quantity of guacamole in one serving = 2.2 ounces
Quantity of guacamole in one batch = 80 ounces
Quantity of guacamole in 25 servings = 2.2*25 = 55 ounces
Guacamole left = Quantity in batch - Quantity of 25 servings
Guacamole left = 
25 ounces of guacamole are still expected to be available from batch.
Keywords: multiplication, subtraction
Learn more about subtraction at:
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