Answer:
The box should have base 16ft by 16ft and height 8ft Therefore,dimensions are 16 ft by 16 ft by 8 ft
Step-by-step explanation:
We were given the volume of the tank as, 2048 cubic feet.
Form minimum weight, the surface area must be minimum.
Let the height be h and the lengths be x
the volume will be: V=x²h then substitute the value of volume, we have
2048=hx²
hence
h=2048/x²
Since the amount of material used is directly proportional to the surface area, then the material needs to be minimized by minimizing the surface area.
The surface area of the box described is
A=x²+4xh
Then substitute h into the Area equation we have
A= x² + 4x(2048/x²)
A= x² + 8192/x
We want to minimize
A
dA/dx = -8192/x² + 2 x= 0 for max or min
when dA/dx=0
dA/dx= 2x-8192/x²=0
2x=8192/x²
Hence
2x³=8192
x³=4096
x=₃√(4096)
X=16ft
Then h=2048/x²
h=2048/16²
h=8ft
The box should have base 16ft by 16ft and height 8ft
Hence the dimensions are 16 ft by 16 ft by 8 ft
Answer:
The range is from 147 to 153 orders per day
Step-by-step explanation:
orders varies by 2% means that orders can be LOWER THAN THE AVERAGE, or HIGHER THAN THE AVERAGE.
That is, by 2%.
First, we need to find the decimal of 2%, so
2/100 = 0.02
We multiply this with the average number of order, 150, to get the varying amount:
0.02 * 150 = 3
Thus, the range would be:
150 - 3 = 147
150 + 3 = 153
The range is from 147 to 153 orders per day
So 2.5 os to 50, aka 2.5:50
divide each side by 2.5 to get the answer.
if you dont have a calculator, divide each side by 5 to get .5:10, multiply by 2 to get 1:20
Answer:
okay i will answer but i dont see the question
Step-by-step explanation:
