Average rate of change means find the slope of the secant line. So if there is a function f(x) and you want to find the average R.O.C over the interval [a,b], it would be (f(b)-f(a))/(b-a)
1. (f(3)-f(1))/(3-1)= (0-(-2))/2= 1, so D.
2. Same concept; (8-4)/(3-1)=2, so A.
3. Again, (39-(-1))/5= 8, B.
Answer:
A = (-1,5) or (-1,-3)
Step-by-step explanation:
A = (-1,y) B = (2,1)
(Distance from A to B) = √[(-1-2)² + (y-1)²] = 5
=√[9 + y² - 2y + 1] = 5
Squaring on both sides
= y² - 2y + 10 = 25
=y² - 2y -15 = 0
= (y-5)(y+3) = 0
y = 5 or -3
Therefore, A = (-1,5) or (-1,-3)
P =$3000, r = 28% , t = 5 years
<span>A = 3000.e^(0.28)(5) = 3000.(4.0551) = $12,165.60</span>
Answer: A
Step-by-step explanation:
First, the problem is g(f(x)). You would plug in f(x) wherever you see an x in g(x). To find the domain, you take the bottom function, and set it equal to 0.

When you solve that, you get x=2. You know your domain is x≥2, but there is as asymptote at x=11. That means the graph never reaches x=11, but gets very close. You find that by setting the entire equation equal to 0 and solve from there.
Answer:x=6
Step-by-step explanation: Remove the radical by raising each side to the index of the radical