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Bogdan [553]
3 years ago
14

Terri brought 1.74 meters of rope. Gracie brought 1.64 meters of rope. Who brought more rope

Mathematics
1 answer:
vredina [299]3 years ago
8 0

Answer: Terri brought 10 more centimeters of rope than Gracie.

Step-by-step explanation:

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James earned $334 for working a 40-hour week how much will he earn in a week in which he works only 32 hours
atroni [7]

$267.20

Divide $334 by 40 for hourly rate then multiply by 32

earnings = \frac{334}{40} × 32 = $267.20


4 0
3 years ago
A jogger started a course and jogged at an average speed of 4 mph. One hour later, a cyclist started the same course and cycled
Anna007 [38]
4/(11-4)=4/7hours :D
6 0
3 years ago
Graph the function<br> Need help ASAP plz
sattari [20]

Given:

The equation of a function is

y=(x-4)^2+1

To find:

The graph of the given function.

Solution:

The vertex form of a parabola is

y=(x-h)^2+k        ...(i)

Where, (h,k) is vertex of the parabola.

We have,

y=(x-4)^2+1         ...(ii)

From (i) and (ii), we get

h=4, k=1

The vertex of the parabola is (4,1).

Now, the table of values is

x             y

2            5

3            2

4             1

5            2

6            5

Plot these points on a coordinate plane and connect them by a free hand curve.

The graph of given function is shown below.

5 0
3 years ago
The sum of 3y and 5 is 47
Daniel [21]

if 3y + 5 = 47

then

y=14

7 0
3 years ago
Find the extremum of f(x,y) subject to the given constraint, and state whether it is a maximum or a minimum. f(x,y)=4x2 2y2; 3x
nevsk [136]

For given f(x, y) the extremum: (12, 24) which is the minimum.

For given question,

We have been given a function f(x) = 4x² + 2y² under the constraint 3x+3y= 108

We use the constraint to build the constraint function,

g(x, y) = 3x + 3y

We then take all the partial derivatives which will be needed for the Lagrange multiplier equations:

f_x=8x

f_y=4y

g_x=3

g_y=3

Setting up the Lagrange multiplier equations:

f_x=\lambda g_x

⇒ 8x = 3λ                                        .....................(1)

f_y=\lambda g_y

⇒ 4y = 3λ                                         ......................(2)

constraint: 3x + 3y = 108                .......................(3)

Taking (1) / (2), (assuming λ ≠ 0)

⇒ 8x/4y = 1

⇒ 2x = y

Substitute this value of y in equation (3),

⇒ 3x + 3y = 108

⇒ 3x + 3(2x) = 108

⇒ 3x + 6x = 108

⇒ 9x = 108

⇒ x = 12

⇒ y = 2 × 12

⇒ y = 24

So, the saddle point (critical point) is (12, 24)

Now we find the value of f(12, 24)

⇒ f(12, 24) = 4(12)² + 2(24)²

⇒ f(12, 24) = 576 + 1152

⇒ f(12, 24) = 1728                             ................(1)

Consider point (18,18)

At this point the value of function f(x, y) is,

⇒ f(18, 18) = 4(18)² + 2(18)²

⇒ f(18, 18) = 1296 + 648

⇒ f(18, 18) = 1944                            ..............(2)

From (1) and (2),

1728 < 1944

This means, given extremum (12, 24) is minimum.

Therefore, for given f(x, y) the extremum: (12, 24) which is the minimum.

Learn more about the extremum here:

brainly.com/question/17227640

#SPJ4

6 0
2 years ago
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