Ask question

Ask question

All categories

3 years ago

15

How many solutions does the following. system of equations have? 6x-3y= -9 y=2x+3. one solution, infinitely many solutions or no

solution?

1 answer:

DanielleElmas [232]3 years ago

7 0

Answer:

D on edg

Step-by-step explanation:

You might be interested in

What does increase mean

Darya [45]

Increase- to be more significant in value, to be of more worth, to have a larger quantity.

Basically, if I said I added 2 to 5, that would be an increase.

2+5=7 7 is bigger than 5.

If I subtracted 2 from 5, that would make a decrease in value.

5-2=3 3 is smaller than 5.

I hope this helps!
~kaikers

8 0

3 years ago

Need help please !!Solve the inequality. Show your work please(:<br> 5y +16≤56

yan [13]

Hope this can help u

3 0

3 years ago

Read 2 more answers

What is the perimeter of the square 3 by 3

Tema [17]

Answer:12cm

Step-by-step explanation:3+3+3+3 because its 3x3 so their is 3cm on each side

5 0

3 years ago

natka813 [3]

Answer:

<h2>2. D. 64</h2><h2>5. B. 1, -3/2</h2><h2>6. C. 0, 2</h2>

Step-by-step explanation:

$2.\\(a-b)^2=a^2-2ab+b^2\\\\x^2-16x=-8\\\\x^2-2(x)(8)=-8\\\\\text{We have}\ 2ab=2(x)(8).\ \text{Therefore}\ b=8.\\\\x^2-2(x)(8)=-8\qquad\text{add}\ 8^2=64\ \text{to both sides}\\\\x^2-2(x)(8)+8^2=-8+64\\\\(x-8)^2=56$

$5.\\2x^2+x-1=2\qquad\text{subtract 2 from both sides}\\\\2x^2+x-3=0\\\\2x^2+3x-2x-3=0\\\\x(2x+3)-1(2x+3)=0\\\\(2x+3)(x-1)=0\iff 2x+3=0\ \vee\ x-1=0\\\\2x+3=0\qquad\text{subtract 3 from both sides}\\2x=-3\qquad\text{divide both sides by 2}\\\boxed{x=-\dfrac{3}{2}}\\\\x-1=0\qquad\text{add 1 to both sides}\\\boxed{x=1}$

$6.\\2x^2-4x=0\qquad\text{divide both sides by 2}\\\\x^2-2x=0\\\\x(x-2)=0\iff x=0\ \vee\ x-2=0\\\\\boxed{x=0}\\\\x-2=0\qquad\text{add 2 to both sides}\\\boxed{x=2}$

8 0

3 years ago

If anyone knows how to solve this I’d really appreciate it :)

ratelena [41]

The correct answer is C) 71

7 0

3 years ago