Answer: ( 77.27 , 83.93)
Therefore at 95% confidence/prediction interval is
= ( 77.27 , 83.93)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 80.6 words per minute
Standard deviation r = 7.2
Number of samples n = 18
Confidence interval = 95%
z(at 95% confidence) = 1.96
Substituting the values we have;
80.6+/-1.96(7.2/√18)
80.6+/-1.96(1.697056274847)
80.6 +/- 3.33
= ( 77.27 , 83.93)
Therefore at 95% confidence/prediction interval is
= ( 77.27 , 83.93)

$=\sqrt{4^2}\times\sqrt{2^2\cdot3}$
$=4\times2\sqrt3=8\sqrt3$
Step-by-step explanation:
The slopes of perpindicular lines must be negative reciprocals of each other -- while -4 and 4 are negative to each other, the negative recipricocal for -4 is 1/4 and -1/4 for 4.
The slopes of parallel lines must be the same, so these are not parallel.
145,973 Is decimaled in 145.
14.5
1.45
.145
Looking at the chart, we can see that with diet chow, the weight changed by -26, while with kitty diet, it changed by -13. Therefore, the Diet Chow was more effective