A circular swimming pool has a radius of 15 ft. There is a path all around that pool that is three feet wide.

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

6 0

Answer:

Circumference(C) of the circle is given by:

$C = 2 \pi r$

where, r is the radius of the circle.

As per the statement:

A circular swimming pool has a radius of 15 ft.

⇒radius of the pool(r) = 15 ft

There is a path all around that pool that is three feet wide.

⇒radius of the outer edge of the path around the pool(r') = 15 +3 = 18 ft

Substitute these in the formula we have;

$C = 2 \pi r'$

⇒ $C = 2 \cdot 3.14 \cdot 18 = 113.04 ft$

Therefore, the circumference of the outer edge of the path around the pool is, 113.04 ft

belka [17]3 years ago

3 0

Answer:

Step-by-step explanation:

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Use Euclid's division algorithm to find the HCF of 441, 567, 693

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Let a = 693, b = 567 and c = 441

Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under

693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63

Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63

441 = 63 x 7+0
=> HCF of 441 and 63 is 63.

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6 0

3 years ago

C=59(F−32)

neonofarm [45]

I says every time you INCREASE by 1 degree Farenheit you go up 59 degrees C, so it is false. Same for III, if you go up or down 1 degree C that's not a change of 59 in degrees F.

That leaves B, which is right if you experiment with the math.

8 0

3 years ago

I will give brainliest to people who answer ALL 5 questions.

amid [387]

Here ya go. Hope this helps. Have a great day