Answer: 601
Step-by-step explanation:
When the prior estimate of population proportion is not given , the formula we apply to find sample size :
![n=0.25(\dfrac{z^*}{E})^2](https://tex.z-dn.net/?f=n%3D0.25%28%5Cdfrac%7Bz%5E%2A%7D%7BE%7D%29%5E2)
, where z* = critical z-value
E=Margin of error
Given : Margin of error = 0.04
Confidence level = 95%
We know that , according to the z-table , the critical value for 95% confidence interval = z*= 1.960
Then, the required sample size : ![n=0.25(\dfrac{1.960}{0.04})^2](https://tex.z-dn.net/?f=n%3D0.25%28%5Cdfrac%7B1.960%7D%7B0.04%7D%29%5E2)
![n=0.25(49)^2](https://tex.z-dn.net/?f=n%3D0.25%2849%29%5E2)
![n=0.25(2401)=600.25\approx601](https://tex.z-dn.net/?f=n%3D0.25%282401%29%3D600.25%5Capprox601)
Hence, the required minimum sample size = 601