Answer:
Student A and Student B both answered 2 questions correctly.
See explanation below
Step-by-step explanation:
Note: that answers in the form:

ARE ALL EQUIVALENT.
First of all, 4/5 is equivalent to 0.8 if we do long division.
and 19/20 is 0.95 if we do long division.
Now, <u>Student A:</u>
Both of the fractions are correct and the negative sign is equivalent and makes the answer correct, so both are correct.
For <u>Student B:</u>
Similarly, both answers are correct for this student as well, looking at the equivalence we showed first.
Also, "-" (negative) in front of the parenthesis and inside parenthesis here doesn't matter.
Hence,
Student A and Student B both answered 2 questions correctly.
let's firstly convert the mixed fraction to improper fraction, and then divide it by 4 to see what our quotient is.
![\bf \stackrel{mixed}{2\frac{1}{4}}\implies \cfrac{2\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{9}{4}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{9}{4}\div 4\implies \cfrac{9}{4}\div \cfrac{4}{1}\implies \cfrac{9}{4}\cdot \cfrac{1}{4}\implies \cfrac{9}{16}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Bmixed%7D%7B2%5Cfrac%7B1%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B2%5Ccdot%204%2B1%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B9%7D%7B4%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B9%7D%7B4%7D%5Cdiv%204%5Cimplies%20%5Ccfrac%7B9%7D%7B4%7D%5Cdiv%20%5Ccfrac%7B4%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B9%7D%7B4%7D%5Ccdot%20%5Ccfrac%7B1%7D%7B4%7D%5Cimplies%20%5Ccfrac%7B9%7D%7B16%7D)
Answer:
31/-45
Step-by-step explanation:
rise is 31(-8 to 23) and run is -45 since you are going from 30 to -15
Answer:
Segment AB || Segment CD
Step-by-step explanation:
Two lines are said to be parallel (||) if they do not meet, even when extended to infinity.
Given: <1 ≅ <3, ΔACD is an isosceles triangle.
Proof: Segment AB || Segment CD
From the diagram given,
AC ≅ AD (side property of isosceles triangle)
<3 = <4 (base angle property of an isosceles triangle)
<1 = <4 (alternate angle property)
Therefore, segment AB is parallel to segment CD.