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3 years ago

Liam has 9/10 gallon of paint for painting the birdhouses he sells at the

2 answers:

5 0

We know two things: The first is that Liam has 9/10 gallon of paint and the second is that each birdhouse requires 1/20 gallon of paint.
In order to calculate how many birdhouse Lian can paint with 9/10 gallon of paint we should divide 9/10 with 1/20:
(9/10) / (1/20)= 9*20/10=180/10=18
So, Liam can paint 18 birdhouses.

Archy [21]3 years ago

4 0

Liam has 9/10 of a gallon of paint, this quantity is the same as 18/20, that is,
9/10 = 18/20
9 and 10 are multiply by 2 to get 18 and 20 so that the fraction of paint available will have the same denominator as the quantity of paint that each bird house required.
The quantity of paint available is 18/20 and each house bird requires a quantity of 1/20 of gallon of paint, this means that 18 bird houses can be painted with the quantity of paint available.

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What is the solution of 1/3b = -3

Tcecarenko [31]

Simplify 1/3b to b/3

b/3 = -3

multiply both sides by 3

b = -3 * 3

multiply 3 * 3 so it can = 9

Answer: b = -9

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2 years ago

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Please help with #1 and explain your answers! Thank you

sashaice [31]

1a) False. A square is never a trapezoid. A trapezoid has only one pair of parallel sides while the other set of opposite sides are not parallel. Contrast this with a square which has 2 pairs of parallel opposite sides.

1b) False. A rhombus is only a rectangle when the figure is also a square. A square is essentially a rhombus and a rectangle at the same time. If you had a Venn Diagram, then the circle region "rectangle" and the circle region "rhombus" overlap to form the region for "square". If the statement said "sometimes" instead of "always", then the statement would be true.

1c) False. Any rhombus is a parallelogram. This can be proven by dividing up the rhombus into triangles, and then proving the triangles to be congruent (using SSS), then you use CPCTC to show that the alternate interior angles are congruent. Finally, this would lead to the pairs of opposite sides being parallel through the converse of the alternate interior angle theorem. Changing the "never" to "always" will make the original statement to be true. Keep in mind that not all parallelograms are a rhombus.

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2 years ago

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-2x + 9x What is the answer

Blababa [14]

Answer: $7x$

Remove "x" and add

-2 + 9 = 7

Add "x" back

7 -----> 7x

Note: When adding/subtracting problems like these remove "x" and then add/subtract normaly. When you get your answer put x back.

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3 years ago

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What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

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2 years ago

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It is estimated that 26% of the population of Gingerland have red hair. If 10 residents are chosen at random, what is the probab

sveticcg [70]

Answer:

The answer for me would be a) exactly 4 of them have red hair

Step-by-step explanation:

being that there is 26 percent of people in Gingerland that gave red hair I cam assume that that is a lot of people being that Gingelrand is like a city/town so exactly 4 of them is what I assume is the amswer

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