Answer:
* y = x² is a quadratic function represented graphically by parabola opened upward with minimum vertex (0 , 0) and y-intercept = 0
* The graph will move vertically up 5 units and its vertex will be
(0 , 5)
Step-by-step explanation:
∵ y = ax² + bx + c is a quadratic function
Represented graphically by parabola, its vertex is (-b/2a , f(-b/2a))
∵ The value of a > 0 then the parabola open upward
∴ Its vertex is minimum
∵ The value of a < 0 then the parabola oped downward
∴ Its vertex is maximum
∵ The coefficient of x² = 1
∴ The parabola open upward
∵ The coefficient of x = 0
∴ Its vertex is (0 , 0) ⇒ x = 0/2(1) = 0 , f(0) = (0)² = 0
∴ The y-intercept = 0
∴ The parabola is oped upward , has minimum vertex (0 , 0)
and passing through the origin
∵ 5 is added to y = x² , that means we add 5 to f(x) ⇒ f(x) + 5
∴ y = x² + 5 ⇒ that means the graph move vertically up 5 units
∴ Its vertex will be (0 , 5)
