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nasty-shy [4]
3 years ago
9

What is 3 5/8 *1 3/4

Mathematics
2 answers:
IrinaVladis [17]3 years ago
4 0

Answer:4/2

Step-by-step explanation:

Rashid [163]3 years ago
3 0
ANSWER: It will be 3/4
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Pleas help me, i'm not sure which one it is and i think it is 10 students got off the bus every minute, please let me know if i'
DanielleElmas [232]

Answer:

The yellow box.

Step-by-step explanation:

According to the graph, 10 students get off the bus every 2 minutes. Do 10 divided by 2 to find out how many students get off the bus each minute. Since the answer is 5, that means 5 students get off the bus each minute.

6 0
3 years ago
are this calculations correct? 65-32=34 and 47+39=86.Show how you could check this using the inverse.
Alexxandr [17]
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5 0
3 years ago
Read 2 more answers
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
Determine if the relationship is a function &amp; explain why and why not.
padilas [110]
No the following coordinates do not show a function because of the y-values. In the pairs that you have, (3,5) and (0,5) have the y-values of "5" that are repeating.

Hope this helps. I learned that in math.
5 0
3 years ago
Piz help me fast asap thx​
Effectus [21]

Answer:

y= 7703.5

Step-by-step explanation:

multiply 7100 by 1.085

5 0
3 years ago
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