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Olegator [25]
3 years ago
15

Gabriela 30 in of ribbon to make bows each bow uses 5 in of ribbon how many ribbons dose Gabriela make

Mathematics
1 answer:
Shalnov [3]3 years ago
3 0

Answer:

Gabriela Can Make 6 Bows.

Step-by-step explanation:

30 ÷ 5 = 6

So Gabriela Has Enough Ribbon To Make 6 Bows.

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Show that if n is an integer and n^3 + 5 is odd then n is even
Salsk061 [2.6K]
If n is odd then its cube is also odd because odd times odd is odd. When we add 5, an odd number, we get an even number.
If n is even, its cube is also even so adding an odd number makes the sum odd. So if the expression is odd, n must be even.
3 0
3 years ago
Please answer number one and number two
PIT_PIT [208]

your answers would be 4 and 2

4 0
3 years ago
A $ 240 suit is maker down by 20% find the sale price
Annette [7]

Answer:

192

Step-by-step explanation:

4 0
3 years ago
The mean of 100 observation is found to be 40. If at the time of compution two items were wrongly taken as 30 and 27 instead of
Colt1911 [192]

Answer:

40.18

Step-by-step explanation:

According to this question, the mean of 100 observation is found to be 40. This means that the number of values in the set of data is 100. However, at the time of computation two items were wrongly taken as 30 and 27 instead of 3 and 72.

The mean is derived by dividing the sum of values in the data (Σx) by the number of observations (n) i.e.

Mean = Σx/n

For the computation error:

Mean = 40

Let x represent the sun of other 98 values except 30 and 27

n = 100

40 = x + 30 + 27/100

40 = 57 + x/100

Cross multiply

4000 = 57 + x

x = 4000 - 57

x = 3943.

Sum of other 98 values = 3943.

Now, let's find the correct mean with correct values of 3 and 72;

Mean = Σx/n

Mean = 3943 + 3 + 72/100

Mean = 4018/100

Mean = 40.18

7 0
3 years ago
Will mark the Brainliest !!!!! A team of 5 boys and 4 girls will be chosen from a group of 16 boys and 13 girls,
vfiekz [6]

Answer:

Step-by-step explanation:

The total number of permutations of boys and girls on the team are:

¹⁶P₅*¹³P₄

1.

Bob will be one of the fixed boys to be picked. Hence, actually 4 boys are to be picked from 15. The permutations of girls being picked remains the same.

Probability = Permutations with Bob as one of the boys / Total permutations

Probability = (¹⁵P₄*¹³P₄) / (¹⁶P₅*¹³P₄) = ¹⁵P₄ / ¹⁶P₅

Probability = \frac{15!}{(15-4)!}/\frac{16!}{(16-5)!} = 15! / 16! = 1/16

2.

Now, Bob is one of the fixed boys and Jane is one of the fixed girls. Hence, actually 4 boys are to be picked from 15 and 3 girls are to be picked from 12.

Probability = Permutations with bob as one of the boys and jane as one of the girls / Total permutations

Probability = (¹⁵P₄*¹²P₃) / (¹⁶P₅*¹³P₄) = (1/16)*(1/13) = 1/208

3.

Now, the probability that at least Jane or Bob will be picked has been asked. This probability is a combination of three probabilities:

Probability = (Probability that only Bob will be picked) + (Probability that only Jane will be picked) + (Probability that both will be picked)

Probability = 1/16 + 1/13 + 1/208 = 0.123

4.

Total teams possible = ¹⁶P₅*¹³P₄ = 8994585600 teams are possible

5 0
3 years ago
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