78% of 3 feet is 28.08 inches
Answer:
See attached picture
Step-by-step explanation:
To graph, use y=mx+b as a guide where m is the slope and b is the y-intercept.
y=-3x-4
Start at -4 on the y-axis. Plot a point. This is the y-intercept b. From this point count down 3 units and 1 unit to the right. Plot this point and connect.
y=3/4x +2
Start at 2 on the y-axis. Plot a point. This is the y-intercept b. From this point count up 3 units and 4 units to the right. Plot this point and connect.
The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
Read more about Maximization of Area at; brainly.com/question/13869651
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Answer:
Perimeter of the rectangle=6x+8 square units
Step-by-step explanation:
Given that area of rectangle is 
Area of rectangle=lw square units
Comparing the above equation with the given area we get
lw=(x+3)(2x+1)
Therefore length=x+3 and width=2x+1
To find the perimeter :
Perimeter of the rectangle=2(l+w) square units
Therefore perimeter of the rectangle=6x+8 square units
Answer:
estimate 4,164 which is 4,000 then estimate 137 which is 100
Step-by-step explanation:
then you will multipley it then find the estimated answer then muiltyply 4,164 and 137
