Ask question

Ask question

All categories

3 years ago

7

Local newspaper company wanted to determine if there is a need for a digital version of their newspaper. They sampled 80 of thei

r subscribers and determined that 56 of them would be interested in the new services .
A.) what is the sample proportion

B.) if the total number of subscribers for the newspaper is 138,246 what would be the estimated number of subscribers who would be interested in the new digital version ?

1 answer:

Oksana_A [137]3 years ago

3 0

Answer:

A.) 7:3

B.) Approximately 96,772 people

Step-by-step explanation:

The newspaper company sampled 80 of their subscribers.

56 of the 80 would be interested in the new services.

So, 80 - 56 = 24 people would not be interested in the new service.

The ratio of those interested in the new service to those who are not interested is:

56 : 24 simplified becomes 7 : 3 (We divide 56 and 24 by a common divisor = 8)

If the total number of subscribers for the newspaper is 138,346

The number of subscribers who would be interested in the new service would be:

$\frac{7}{10}$ × 138,246 = 96,772.2 people

Because there are no 0.2 people, we remove the decimal point of the answer and hence;

Approximately 96,772 people would be interested in the new service.

You might be interested in

Solve for n. 2n − 35=52n − 35=5

melomori [17]

The answer is n= 35/2

7 0

3 years ago

Read 2 more answers

A regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. what is the approximate area

aniked [119]

The area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².

<h3>What is the area of a heptagon?</h3>

Heptagon is the closed shape polygon which has 7 sides and 7 interior angles.

The area of the regular heptagon is found out using the following formula.

$A=\dfrac{7a}{4}\cot \left(\dfrac{180}{7}\right)$

Here, (<em>a</em>) is the length of the heptagon.

A regular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. Put the value of side in the above formula,

$A=\dfrac{7\times24.18}{4}\cot \left(\dfrac{180}{7}\right)\\A\approx 2125\rm\; cm^2$

Hence, the area of the regular heptagon which has a radius of approximately 27.87 cm and the length of each side is 24.18 cm is 2125 cm².

Learn more about the area of a heptagon here;

brainly.com/question/26271153

3 0

2 years ago

What is the answer for 10-6(5-2y)

grin007 [14]

Answer:

-20 + 12y

Step-by-step explanation:

Equation: 10 - 6(5 - 2y)

Step 1:

10 - 30 + 12y Multiply (5 - 2y) by -6 (distributive property)

Step 2:

-20 + 12y Subtract 10 by 30 (10 - 30 = -20)

8 0

3 years ago

Read 2 more answers

In the triangle pictured, let A, B, C be the angles at the three vertices, and let a,b,c be the sides opposite those angles. Acc

Troyanec [42]

Answer:

Step-by-step explanation:

(a)

Consider the following:

$A=\frac{\pi}{4}=45°\\\\B=\frac{\pi}{3}=60°$

Use sine rule,

$\frac{b}{a}=\frac{\sinB}{\sin A}
\\\\=\frac{\sin{\frac{\pi}{3}}
}{\sin{\frac{\pi}{4}}}\\\\=\frac{[\frac{\sqrt{3}}{2}]}{\frac{1}{\sqrt{2}}}\\\\=\frac{\sqrt{2}}{2}\times \frac{\sqrt{2}}{1}=\sqrt{\frac{3}{2}}$

Again consider,

$\frac{b}{a}=\frac{\sin{B}}{\sin{A}}
\\\\\sin{B}=\frac{b}{a}\times \sin{A}\\\\\sin{B}=\sqrt{\frac{3}{2}}\sin {A}\\\\B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]$

Thus, the angle B is function of A is, $B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]$

Now find $\frac{dB}{dA}$

Differentiate implicitly the function $\sin{B}=\sqrt{\frac{3}{2}}\sin{A}$ with respect to A to get,

$\cos {B}.\frac{dB}{dA}=\sqrt{\frac{3}{2}}\cos A\\\\\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos A}{\cos B}$

b)

When $A=\frac{\pi}{4},B=\frac{\pi}{3}$ , the value of $\frac{dB}{dA}$ is,

$\frac{dB}{dA}=\sqrt{\frac{3}{2}}.\frac{\cos {\frac{\pi}{4}}}{\cos {\frac{\pi}{3}}}\\\\=\sqrt{\frac{3}{2}}.\frac{\frac{1}{\sqrt{2}}}{\frac{1}{2}}\\\\=\sqrt{3}$

c)

In general, the linear approximation at x= a is,

$f(x)=f'(x).(x-a)+f(a)$

Here the function $f(A)=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{A}]$

At $A=\frac{\pi}{4}$

$f(\frac{\pi}{4})=B=\sin^{-1}[\sqrt{\frac{3}{2}}\sin{\frac{\pi}{4}}]\\\\=\sin^{-1}[\sqrt{\frac{3}{2}}.\frac{1}{\sqrt{2}}]\\\\\=\sin^{-1}(\frac{\sqrt{2}}{2})\\\\=\frac{\pi}{3}$

And,

$f'(A)=\frac{dB}{dA}=\sqrt{3}$ from part b

Therefore, the linear approximation at $A=\frac{\pi}{4}$ is,

$f(x)=f'(A).(x-A)+f(A)\\\\=f'(\frac{\pi}{4}).(x-\frac{\pi}{4})+f(\frac{\pi}{4})\\\\=\sqrt{3}.[x-\frac{\pi}{4}]+\frac{\pi}{3}$

d)

Use part (c), when $A=46°$ , B is approximately,

$B=f(46°)=\sqrt{3}[46°-\frac{\pi}{4}]+\frac{\pi}{3}\\\\=\sqrt{3}(1°)+\frac{\pi}{3}\\\\=61.732°$

8 0

3 years ago

company paid $48 for 2 cases of printer paper. Each case contained 12 packages of paper. Next month the company’s office manager

Paha777 [63]

Answer:

the answer would be 384 dollars

4 0

3 years ago