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labwork [276]
3 years ago
10

In the year 2000, the number of foxes in a

Mathematics
1 answer:
Andrews [41]3 years ago
7 0

Answer:

Since the equations involve functions and their derivatives, we might bet- ter call them  If this rate were to persist for 20 years (= 240 months), R would have increased by  similar to equation (1) when the number of rabbits R is near 2000, but which The fox population increases at a rate proportional to the number of.

Step-by-step explanation:

i think this it

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Carol sold twice as many magazine subscriptions as Jennifer. If Carol and Jennifer sold 90 subscriptions in all, how many subscr
goblinko [34]
Hello there!

Carol would have sold 60 subscriptions and Jenifer would have sold 30

The correct answer is option D, 60

I hope this help!
3 0
3 years ago
Help me help me 10 points
Shtirlitz [24]

Answer:

arc BC = 84 degrees

Step-by-step explanation:

notice:

need to find n  before finding arc BC

(13n -16) + (7n + 12) + 6n = 360

13n + 7n + 6n  - 16 + 12  = 360

26n  - 4 = 360

26n = 364

n = 364/26  = 14

so arc BC = 6*14 = 84 degrees

3 0
3 years ago
Simplify: (7+2a)·3–20 =
Black_prince [1.1K]
<h2>Greetings!</h2>

Answer:

6a + 1

Step-by-step explanation:

First, you need to multiply everything in the brackets by 3L

(7 + 2a) x 3 =

7 * 3 = 21

2a *  3 = 6a

21 + 6a

Now you can subtract the 20 from this:

6a + 21 - 20

Simplified down:

6a + 1


<h2>Hope this helps!</h2>
6 0
3 years ago
If r=20.5 and s=34.2 find S Round to the nearest tenth
astraxan [27]

Answer: option d

Step-by-step explanation:

Remember the identity:

tan\alpha=\frac{opposite}{adjacent}

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "S":

 \alpha =arctan(\frac{opposite}{adjacent})

Knowing that: you need to find the measure of the angle "S" , r=20.5 (which is the adjacent side) and s=34.2 (which is the opposite side), you can sustitute values into \alpha =arctan(\frac{opposite}{adjacent})

Then, you get that the measure of "S" rounded to the nearest tenth is:

S=arctan(\frac{34.2}{20.5})\\\\S=59.1\°

7 0
4 years ago
Read 2 more answers
The atmospheric pressure at sea level is 14.7 lb/in2. This pressure is reduced by half for each 3.6 miles above sea level. Which
Nina [5.8K]
It could be a linear graph with a negative slope 
x axis  is height above ground and y axis id air pressure
so there willbe a point  at (0,14.7) on y axis representing the pressure at sea level. There will be another point at (3.6, 7.35) where  air pressure is half that at ground level. The straight line will continue until it reaches the x axis  ad (0, 7.2)  where there is no air pressure.
4 0
4 years ago
Read 2 more answers
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