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2 years ago

a fair cube has 2 red sides, 2 blue sides, and 2 green sides what is the probability of rolling red or blue

Mathematics

1 answer:

True [87]2 years ago

5 0

The probability of rolling red or blue would be 4 out of 6 4/6

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A box of muffin mix has dimensions of 5 3/8 inches by 3 inches by 1 5/8 inches. What is the volume of the box? 15 15/64 cubic in

anyanavicka [17]

Answer is 26 13/64

first u need to simplify mixed number then multiply them all

43/8*3*13/8=1677/64

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3 years ago

Read 2 more answers

The perimeter of a square is 44 centimeters. what is its area?

aalyn [17]

Answer:

Perimeter = 44cm

we know that square has 4 sides which are same

so perimeter means sum of all 4 sides

4 × s = 44cm

s = 11cm

Each side will be of 11cm.

Now area of square is Square of its side length.

so area = 11 × 11 = 121 cm^2

8 0

2 years ago

urgent!!!! house has 30 windows. kids playing outside the house 40% of the windows. how many windows are broken?

svetlana [45]

Answer:

12 windows

Step-by-step explanation:

Number of windows broken = 40% of 30

$= \frac{40}{100}*30\\\\= 4 * 3\\\\= 12$

3 0

3 years ago

A 100 gallon tank initially contains 100 gallons of sugar water at a concentration of 0.25 pounds of sugar per gallon suppose th

Vsevolod [243]

At the start, the tank contains

(0.25 lb/gal) * (100 gal) = 25 lb

of sugar. Let $S(t)$ be the amount of sugar in the tank at time $t$ . Then $S(0)=25$ .

Sugar is added to the tank at a rate of P lb/min, and removed at a rate of

$\left(1\frac{\rm gal}{\rm min}\right)\left(\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm gal}\right)=\dfrac{S(t)}{100}\dfrac{\rm lb}{\rm min}$

and so the amount of sugar in the tank changes at a net rate according to the separable differential equation,

$\dfrac{\mathrm dS}{\mathrm dt}=P-\dfrac S{100}$

Separate variables, integrate, and solve for S.

$\dfrac{\mathrm dS}{P-\frac S{100}}=\mathrm dt$

$\displaystyle\int\dfrac{\mathrm dS}{P-\frac S{100}}=\int\mathrm dt$

$-100\ln\left|P-\dfrac S{100}\right|=t+C$

$\ln\left|P-\dfrac S{100}\right|=-100t-100C=C-100t$

$P-\dfrac S{100}=e^{C-100t}=e^Ce^{-100t}=Ce^{-100t}$

$\dfrac S{100}=P-Ce^{-100t}$

$S(t)=100P-100Ce^{-100t}=100P-Ce^{-100t}$

Use the initial value to solve for C :

$S(0)=25\implies 25=100P-C\implies C=100P-25$

$\implies S(t)=100P-(100P-25)e^{-100t}$

The solution is being drained at a constant rate of 1 gal/min; there will be 5 gal of solution remaining after time

$1000\,\mathrm{gal}+\left(-1\dfrac{\rm gal}{\rm min}\right)t=5\,\mathrm{gal}\implies t=995\,\mathrm{min}$

has passed. At this time, we want the tank to contain

(0.5 lb/gal) * (5 gal) = 2.5 lb

of sugar, so we pick P such that

$S(995)=100P-(100P-25)e^{-99,500}=2.5\implies\boxed{P\approx0.025}$

5 0

2 years ago

Which equation best represents the line? y = x 4 y = x 4 y = 4x y = 4x?

Alik [6]

Hello :
equation best represents the line is : y = 4x

8 0

2 years ago