The equation of the line is y = -11x + 232
<h3>How to determine the equation?</h3>
The given parameters are:
Slope (m)= -11
Point (x1, y1) = (31, -109)
The linear equation is then calculated as:
y = m(x - x1) + y1
This gives
y = -11(x - 31) - 109
Evaluate the product
y = -11x + 341 - 109
Evaluate the like terms
y = -11x + 232
Hence, the equation of the line is y = -11x + 232
Read more about linear equations at:
brainly.com/question/14323743
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Answer:
0 = -6
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−2(−2k+3)+4k=−2(6−3k)+2k
(−2)(−2k)+(−2)(3)+4k=(−2)(6)+(−2)(−3k)+2k(Distribute)
4k+−6+4k=−12+6k+2k
(4k+4k)+(−6)=(6k+2k)+(−12)(Combine Like Terms)
8k+−6=8k+−12
8k−6=8k−12
Step 2: Subtract 8k from both sides.
8k−6−8k=8k−12−8k
−6=−12
Step 3: Add 6 to both sides.
−6+6=−12+6
0=−6
Answer:
120 m east & straight i think
The answer would be: 5 + 9u
You would just do 5.7-8.1, which is -3.6 degrees Celcius. Hope I helped!
