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Kaylis [27]
3 years ago
7

Find the common difference for the given sequence. Type a numerical answer in the space provided. Do not include spaces in your

answer. If necessary, use the / key to represent a fraction bar. 56, 49, 42, 35, ...
Mathematics
2 answers:
Blizzard [7]3 years ago
4 0
The answer is -7....
Darina [25.2K]3 years ago
4 0

Answer: -7

Step-by-step explanation:

  • The common difference of an Arithmetic progression is the difference between any two consecutive terms.

i.e. for sequence a_1, a_2, a_3 ,.....

Common difference = d=a_2-a_1=a_3-a_2=a_4-a_4

The given sequence : 56, 49, 42, 35, ...

Then , Common difference =49-56=-7

Hence, the  common difference for the given sequence. =-7

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Select the two binomials that are factors of this trinomial.
Stella [2.4K]

we are given

trinomial as

x^2 -x -12

now, we can factor it

x^2 -x -12= x^2 -4x +3x -4*3

x^2 -x -12= x(x -4) +3(x -4)

x^2 -x -12= (x-4)(x+3)

so, option-C and D ..............Answer

4 0
3 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
3 years ago
Write each fraction as a percent 4/100
nadezda [96]

Answer:

4%is the answer you are looking for

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Nastasia [14]
The answer would be 9
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