Answers:
Part A: 12y² + 10y – 21
Part B: 4y³ + 6y² + 6y – 5
Part C: See below.
Explanations:
Part A:
For this part, you add Sides 1, 2 and 3 together by combining like terms:
Side 1 = 3y² + 2y – 6
Side 2 = 4y² + 3y – 7
Side 3 = 5y² + 5y – 8
3y² + 2y – 6 + 4y² + 3y – 7 + 5y² + 5y – 8
Combine like terms:
3y² + 4y² + 5y² + 2y + 3y + 5y – 6 – 7 – 8
12y² + 10y – 21
Part B:
You have the total perimeter and the sum of three of the sides, so you just need that fourth side value, which we can call d.
P = 4y³ + 18y² + 16y – 26
Sides 1, 2 & 3 = 12y² + 10y – 21
Create an algebraic expression:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
Solve for d:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
– 12y² – 12y²
10y – 21 + d = 4y³ + 6y² + 16y – 26
– 10y – 10y
– 21 + d = 4y³ + 6y² + 6y – 26
+ 21 + 21
d = 4y³ + 6y² + 6y – 5
Part C:
If closed means that the degree that these polynomials are at stay that way, then yes, this is true in these cases because you will notice that each side had a y², y and no coefficient value except for the fourth one. This didn't change, because you only add and subtract like terms.
Answer and Step-by-step explanation:
1. slope intercept
2. point-slope form
3. standard
Explanation:
1.
A <u>slope intercept form</u> equation is when it's set up as y = m x + b
m = slope
b = y-intercept
2. <u>A point-slope form</u> is when a line passes through a point
and the equation is set up as y
−b = m (
x−a)
m = slope
(a, b) A point that the line passes through
3. <u>standard lope form</u> is when the equation is set up as
Ax + By = C
Answer:
-9
Step-by-step explanation:
You take them both and multiply then divide then subtract
Answer:
The range includes all numbers from 5 to 12.5.
Step-by-step explanation:
The range is along y- axis and the domain is along x- axis.
Range is given in heights and domain is given in time seconds.
It can depicted that for t= 0 secs the ball is at 5 feet and so on .
Therefore the range is given by numbers from 5 to 12.5.
Whereas the domain is given by numbers 0 t0 8.5 seconds
