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3 years ago

a cashier at the grocery store rung up 2 customers in 8 minutes. at this rate how many customers can he ring up in 28 minutes?

Mathematics

1 answer:

I am Lyosha [343]3 years ago

5 0

Answer:

7 1/2 customers

Step-by-step explanation:

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Dont undersrand this at allll...

Taya2010 [7]

Answer:

2.3 2 1/3

Step-by-step explanation: you add up all the bikes then divide them by 3 because that's the number of people

4 0

2 years ago

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a bale of hay mesures 2 feet By 2 feet By 3 feet hay weights 8 pound per cubic foot how much does the bale of hay weight

3241004551 [841]

2x2x3=12 12x8=96 so the bale of hay weighs 96 pounds.

6 0

3 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago

*WILL GIVE BRAINLIEST*

andrey2020 [161]

Answer:

The answer is A.

Step-by-step explanation:

I learned it before.

Hope this helps.

3 0

3 years ago

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MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!

Marina CMI [18]

Question 2. :

8^2 = 64 and 9^2 = 81, therefore the square root of 65 falls between these two values, 8 and 9, 64<65<81

Question 3. :

13^2 = 169 and 14^2 = 196, the correct answer is square root of 175, because 169<175<196

Hope this helps, you only need to know the squared values and square roots.

8 0

3 years ago