Answer:
-5
Step-by-step explanation:
Moving all terms of the quadratic to one side, we have
.
A quadratic has one real solution when the discriminant is equal to 0. In a quadratic 
, the discriminant is 
.
(The discriminant is more commonly known as 
, but I changed the variable since we already have a 
in the quadratic given.)
In the quadratic above, we have 
, 
, and 
. Plugging this into the formula for the discriminant, we have
.
Using the distributive property to expand and simplifying, the expression becomes
Setting the discriminant equal to 0 gives
.
We can then solve the equation as usual: first, divide by 2 on both sides:
.
Squaring both sides gives
,
and subtracting 5 from both sides, we have
162/(6(7-4)^2)
pemdas
parenthasees inner first
so 7-4 is forst
7-4=3
162/(6(3)^2)
then exponents
3^2=9
162/(6(9))
multiplication
6 times 9=54
162/(54)=3
Between -2&-1 is the answer
Answer:
x² +18x +81
Step-by-step explanation:
(a+b)²=a²+b²+2ab
(x+9)² = x²+9²+2*x*9= x² +18x +81
Hello!
The letter D is in the place for the upper quartile
To find this you have to find the median of the data
List the numbers from least to greatest
12, 18, 34, 55, 59, 68, 80, 80
The medians are 55 and 59
To get the median we take the average of these numbers
55 + 59 = 114
114 / 2 = 57
The median is 57
To find the upper quartile you find the median of the numbers higher than 57
List the numbers that are higher than 57 in the data
59, 68, 80, 80
Take the average of 68 and 80
68 + 80 = 148
148/2 = 74
The answer is 74
Hope this helps!
