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Ratling [72]
3 years ago
13

Help please! Brainliest will be GIVEN!

Mathematics
1 answer:
Effectus [21]3 years ago
3 0

Answer: d

Step-by-step explanation:

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Which is the graph of the linear function that is represented by the equation Y - 5x-27
Aleksandr [31]

Please attach the graphs

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3 years ago
Connor works part-time at an electronics store. He is paid an hourly rate of $10.25/h and also earns a commission of 3.5% of his
uysha [10]

Answer:

that is the solution to the question

pls note the answer is $771.43 not $71.14

5 0
4 years ago
Can explain that question? please ?& answer
maxonik [38]
If itt says 4×3+6 it is 18 and it means you can either multiply first
5 0
4 years ago
Could use some help on this please
vfiekz [6]

Answer:

x = 15, y = 4

Step-by-step explanation:

To solve this, we have to define the triangles first. Since the triangles are congruent by HL, it means that the hypotenuse and the leg of the triangle are defined to be equal. By flipping one of the triangles upsidedown, we can visualize the hypotenuse of the triangles and the leg of the triangles (which are equal).

The two equations are the following:

x + 1 = 4y

x = y + 11

If I add 1 to both sides of the second equation, I get the following equation:

x + 1 = y + 11 + 1 = y + 12

By comparing this new equation with the first one, we will get:

x + 1 = 4y = y + 12

We can ignore x+1 for now since y can not be solved.

4y = y + 12

By subtracting both sides of this equation by y, we will get.

3y = 12

This solves for y, where

y = 4

Now, we can re-use one of the equations, which is

x = y + 11

Now that we know y is 4, we can plug it into this equation.

x = 4 + 11 = 15

4 0
3 years ago
You are getting a line-up ready for a school kickball game. you have 77 girls and 77 boys. the rules state each child must kick
mezya [45]
1. Since each child kicks the same number of times, it is not important whether he or she kicks 1 time, 2, 3 or more times. So let all of them kick 1 time.

2. assume we start with a girl. We can start with either of the 77 girls, then second is a boy which can be either of the 76, the third is a girl which can be either of the 76 remaining, then the forth is one of the 76 boys...

3. So starting with a girl we have

77*(77)*76*(76)*75*(75)....*2*(2)*1*(1)=77!*77!

4. OR we could have started with a boy, where we would get again 77!*77!

5. Answer: 77!*77!+77!*77!=2(77!)^{2}
3 0
4 years ago
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