First find the slope
the slope of the line that passes through (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-4,3) and (6,-2)
the slope is (-2-3)/(6-(-4))=(-5)/(6+4)=-5/10=-1/2
so
the equation of a line tat passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
use (-4,3)
and we found slope=-1/2
y-3=-1/2(x-(-4))
y-3=-1/2(x+4)
if yo want slope intercept form
y-3=-1/2x-2
y=-1/2x+1
if yo want standard form
1/2x+y=1
x+2y=2
Step-by-step explanation:
x²+4-4x+y²=3
x²+y²-4x+1=0
(f∘g)(x) = f(g(x)) = f(x +2)
= 2(x +2) -1
= 2x +3 . . . . . selection D
Answer:
15a-21
Step-by-step explanation:
could be wrong though
