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monitta
3 years ago
5

Debbi has 17 coins that are all either quarters or dimes. the total value of her money is 3.20

Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0

Answer:

There are 10 quarters and 7 dimes

Step-by-step explanation:

The question asks for the number of quarters and the number of dimes.

Quarters and Dimes equal 17, so let number of quarters be "q" and number of dimes be "d", so we can write:

q + d = 17

We know quarters are worth 0.25 and dimes are worth 0.10 (in dollars) and total value of the coins are 3.20 dollars, thus we can write:

0.25q + 0.10d = 3.20

Let's write the first equation as:

q = 17 - d

Now we substitute this into 2nd equation and solve for d:

0.25q + 0.10d = 3.20

0.25(17 - d) + 0.10d = 3.20

4.25-0.25d+0.10d = 3.20

-0.15d = -1.05

d = 7

Now using this value of d, we now find q:

q = 17 - d

q = 17 - 7

q = 10

There are 10 quarters and 7 dimes

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The sum of three consecutive even numbers is one hundred sixty-two. What is the smallest of the three numbers?
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1




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3 0
3 years ago
Read 2 more answers
What is the value of discontinuity of x^2+8x+4/x^2-x-6? Choices:
Morgarella [4.7K]

Answer:

-2

Step-by-step explanation:

Hello,

First of all, let's check the denominator.

x^2-x-6 \ \ \text{ *** How to factorise it ...? ***}\\\\\text{*** The product of the roots is -6=-2*3 and their sum is 1 ***}\\\\x^2-x-6=x^2-3x+2x-6=x(x-3)+2(x-3)=(x+2)(x-3)

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x^2+8x+4 \ \text{ *** -2 is not a zero as ***}\\\\(-2)^2+8*(-2)+4=4-16+8=-4\\\\\text{*** 3 is not a zero as ***}\\\\3^2+8*3+4=9+24+4=37\\

So we cannot factorise the numerator with (x+2) or (x-3)

Then, -2 and 3 are the the discontinuities of the expression.

There is only -2 in the list, this is the correct answer.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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3 years ago
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