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deff fn [24]
3 years ago
5

B= (x+7) a= (x=1)=180 solve for angle a and b

Mathematics
1 answer:
Andreyy893 years ago
7 0

b=(x+7)a=(x=1)=180 then 37

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What do i type? please help me.
sergij07 [2.7K]

Answer:

x = 10; x = 0

Step-by-step explanation:

x < 29 means x is less than 29. Any number less then 29 is a solution.

For example, pick x = 10. Since 10 < 29, x = 10 is a solution. How do we know x = 10 is a solution?

We start with x < 29.

Now replace x with 10.

10 < 29

Since 10 < 29 is a true statement, then x = 10 is a solution.

Now pick another number less than 29. For example, oick 0.

x = 0 is a solution.

Proof:

x < 29

Replace x with 0:

0 < 29

Since 0 < 29 is a true statement, then x = 0 is a solution.

You can give more solutions just by picking any numbers that are less than 29, such as 1, 2, 3, 15, 28, 23, -5, -18, etc.

Answer: x = 10; x = 0

4 0
3 years ago
Read 2 more answers
What is 12^(2x-8)=15
IgorLugansk [536]
12(2x - 8) = 15
12(2x) - 12(8) = 15
24x - 96 = 15
<u>      + 96 + 96</u>
       <u>24x</u> = <u>111</u>
        24      24
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4 0
4 years ago
Solve (x – 3)2 = 49. Select the values of x. –46 -4 10 52
Fudgin [204]

Answer: x = 55/2

Step-by-step explanation: (x)(2) (-3)(2) = 49                                                       2x-6+6 = 49+6                                                                                                               2x/2 = 55/2                                                                                                                   x = 55/2

I know that my answer isn't a choice for one of the values of x but that's the result that I got when I solved (x–3)2 = 49.

6 0
3 years ago
Every possible cross section of a three-dimensional figure is a circle. What is the figure?
Alex787 [66]
Any point or line, segment, ray, polygon etc.
6 0
3 years ago
Evaluate triple integral ∫ ∫ ∫ 8xydV, where E lies under the plane z = 1+x+y and above the E region in the xy-plane bounded by t
vazorg [7]

Answer:

\mathbf{=\dfrac{163.384}{15}}

Step-by-step explanation:

\int \int \limits_{E} \int \ 8 xy dV = \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} \int\limits^{1+x+y}_{0} \ 8xy dz dydx

= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} [ 8xyz]^{z=1+x+y}_{z=0}  \   \ dy dx

= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy (1+x+y) dy dx

= \int\limits^{1}_{0} \int\limits^{\sqrt{x}}_{0} 8xy+8x^2y+8xy^2 \ \ dy dx

= \int\limits^{1}_{0}  \ [ 4xy^2+4x^2y^2+2.7xy^3]^{ y= \sqrt{x}}_{y-0} \ \  dx

= \int\limits^{1}_{0} \   4x (\sqrt{x})^2+4x^2(\sqrt{x})^2+2.7x(\sqrt{x})^3\ \  dx

= \int\limits^{1}_{0} \   4x^2+4x^3+2.7x^{5/2} \  dx

\mathbf{=\dfrac{163.384}{15}}

7 0
4 years ago
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