Ok this is the answer to this question 2(x+1)
A = 1/2bh
= 1/2(3)(4)
=1/2(12)
=6
The area of the triangle is: B) 6 units.
Hope this helps!
Answer:
a) 0.264
b) 48 cubit light-years
Step-by-step explanation:
For calculating a) What is the probability of 3 or more stars in 16 cubic light years?
a)
λ= 1 star/16 cubic light-years
t= measure t in units of 16 cubic light years.
E(Y) = λ t = (1/16)(16) = 1 star
P(X>=2) = 1 - P(X<2)
= 1 - [e^-1 + (e^-1)(1)/1!]
= 0.264
b)
P(X≥1) = 1 - P(X=0)
= 1 - e^-μ
0.95 = 1 - e^-μ
e^-μ = 1 - 0.95
e^-μ = 0.05
ln(e^-μ) = ln(0.05)
-μ = -3
μ = 3
Therefore 3 x 16 = 48 cubic light years of space
4x-y=8
-4x (subtract -4x from both sides)
-Y=-4x+8
/-y (divide -1y from both sides)
Y=4x-8
answer is: y=4x-8
(4,1)
Trigonometric identity
Substituting with the secant value given:
