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3 years ago

About 1/10 of the human population is left-handed.

Mathematics

2 answers:

meriva3 years ago

7 0

Answer:

If 1/10 of every person is left handed that means that 9/10 people would be right handed, so if 10% of people are left handed then the other 90% would be right handed. Hope this helped! :D

Step-by-step explanation:

zalisa [80]3 years ago

5 0

10% left handed
90%(9/10) right handed
1:9

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Find the zeros of the function algebraically<br> A. f(x) = 2x^2 – 7x = 30<br> B. f(x)=1/3x-2x/4x

Shtirlitz [24]

Answer:

Xi60rs6rodrd6i7yf7tofo7tdto6dt96tf7t9f9

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iogann1982 [59]

It’s the 2nd bubble, 0.664

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4 years ago

5B. Using the balanced seesaw shown, find the ratio of lengths a/b in lowest terms.

zalisa [80]

Answer:

Lowest terms is 7:6

Step-by-step explanation:

A = 63

B = 54

Ratio is a:b = 63:54

63:54

Reduce 63 to lowest terms to get 7 by dividing 9.

63 ÷ 9 = 7

Reduce 54 to lowest terms to get 6 by dividing 9.

54 ÷ 9 = 6

So the reduced form 63:54 in ratio is 7:6.

7:6

I hope this helped!

8 0

3 years ago

Read 2 more answers

Consider the infinite geometric series ∑∞ n=1 -4(1/3)^n-1

erma4kov [3.2K]

a. The series is

$\displaystyle\sum_{n=1}^\infty-4\left(\frac13\right)^{n-1}=-4-\frac43-\frac4{3^2}-\frac4{3^3}-\cdots$

(first four terms are listed)

b. The series converges because this is a geometric series with $r=\dfrac13$ .

c. Let $S_N$ be the $N$ -th partial sum of the series:

$S_N=\displaystyle\sum_{n=1}^N-4\left(\frac13\right)^{n-1}$

$S_N=-4-\dfrac43-\dfrac4{3^2}-\cdots-\dfrac4{3^{N-1}}$

Multiplying both sides by $\dfrac13$ gives

$\dfrac13S_N=-\dfrac43-\dfrac4{3^2}-\dfrac4{3^3}-\cdots-\dfrac4{3^N}$

Subtracting this from $S_N$ gives

$S_N-\dfrac13S_N=\dfrac23S_N=-4+\dfrac4{3^N}$

$\implies S_N=-6+\dfrac6{3^N}$

As $N$ gets larger and larger $(N\to\infty)$ the rational term converges to 0 and we're left with

$\displaystyle\lim_{N\to\infty}S_N=\sum_{n=1}^\infty-4\left(\frac13\right)^{n-1}=-6$

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3 years ago

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barxatty [35]

Answer:

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Step-by-step explanation:

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