Answer (Note: the bold are answers):
First question answer:
Point = (3,1)
Slope = 3
y = 3x + b
(1) = 3(3) + b
1 = 9 + b
1 - 9 = b
-8 = b
y = 3x - 8
The second question answer:
y = mx + b
Get two points:
(3,-7) and (4,-11)
m = -11 - (-7) / 4 - 3
m = -11 + 7 / 1
m = -4 / 1
m = -4
b = + 3
y = -4x + 3
Answer:
x= -9/7
y= -38/7
so it has A. exactly one solution
Step-by-step explanation:
Substitute into one of the equations: 5x+1= -2x-8
Rearrange unknown terms to the left side of the equation: 5x+2x=-8-1
Combine like terms:7x=-8-1
Calculate the sum or difference: 8x=-9
Divide both sides of the equation by the coefficient of variable: x=-9/7
Substitute into one of the equations:y=-2×(-9/7)-8
Write as a single fraction:y=2×9/7-8
Calculate the product or quotient:y=18/7 -8
Convert the expression into a fraction: y=18/7 -8/1
Expand the fraction to get the least common demominator:y=18/7-8x7/1x7
Calculate the product or quotient: y=18/7-56/7
Write the numerators over common denominator:y=18-56/7
Calculate the sum or difference: y=-38/7
Rewrite the fraction: y= -38/7
The solution of the system is:
x= -9/7
y= -38/7
9 - 22 is -13 then add 12 yards equals -1 so they just lost one years from where they started so the answer is -1
Answer:
64
Step-by-step explanation:
Its practically just 8 times 8
Answer: The correct option is (D) P″(9, -12) and Q″(15, -3).
Step-by-step explanation: Given that triangle PQR is dilated by a scale factor of 1.5 to form triangle P′Q′R′. This triangle is then dilated by a scale factor of 2 to form triangle P″Q″R″.
The co-ordinates of vertices P and Q are (3, -4) and (5, -1) respectively.
We are to find the co-ordinates of the vertices P″ and Q″.
<u>Case I :</u> ΔPQR dilated to ΔP'Q'R'
The co-ordinates of P' and Q' are given by

<u>Case II :</u> ΔP'Q'R' dilated to ΔP''Q''R''
The co-ordinates of P'' and Q'' are given by

Thus, the co-ordinates of the vertices P'' and Q'' are (9, -12) and (15, -3).
Option (D) is CORRECT.
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