Question

A local school needs to paint the floor of its theater room, where the length of the floor, x, is at least 11 feet. The width of the floor is 4 feet less than the length. It will have a stage and a closet, and the remaining area of the floor will be painted. The dimensions are shown in the diagram: rectangle with length of x ft and width of x minus 4 ft, right triangle inside labeled stage with height of x minus 4 ft and base of 8 ft, rectangle inside labeled closet with length of 7 ft and width of 3 ft, the rest of the rectangle is labeled floor Let A represent the painted area, in square feet, of the floor. Choose the correct equation to solve for area (A). A = x(x − 4) − (8)(x − 4) − 3(7) A = x(x − 4) + (8)(x − 4) + 3(7) A = x(x − 4) + 0.5(8)(x − 4) + 3(7) A = x(x − 4) − 0.5(8)(x − 4) − 3(7)

Answer 1

Answer:

A = x(x − 4) − 0.5(8)(x − 4) − 3(7)

Step-by-step explanation:

x = length, making the width (x-4)

The stage closet will be (x-4)(8)(1/2)

The rectangle is 7(3)

That makes the painted area x(x-4) - 4(x-4)

So...

A = x(x − 4) − 0.5(8)(x − 4) − 3(7)

Answer 2

Answer:

D

Hope this helps