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Sophie [7]
3 years ago
12

In a scale model of a table, 1 centimeter represents 8 inches.

Mathematics
1 answer:
Trava [24]3 years ago
8 0

Answer:

(a): 6 centimeters

(b): 72 inches

Step-by-step explanation:

Rule: From centimeters to inches, multiply centimeters × 8

so from inches to centimeters, divide inches by 8

Scale:

1 cm : 8 in

? cm : 48 in

6 cm : 48 in

Scale:

? in : 9 cm

72 in : 9 cm

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Answer:

\boxed{ \bold{  \huge{ \boxed{ \sf{1}}}}}

Step-by-step explanation:

\sf{ \frac{1}{2}  \times 2}

Multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

\dashrightarrow{ \sf{ \frac{1 \times 2}{2 \times 1} }}

\dashrightarrow{ \sf{ \frac{2}{2} }}

\dashrightarrow{ \sf{1}}

Or, You can simply reduce the fraction with 2, which results to 1.

Hope I helped!

Best regards! :D

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3 years ago
9 millimeters to centimeters
Oxana [17]
9 millimeters= 0.9 centimeters
6 0
3 years ago
Adrian works in New York City and makes $42 per hour. she works in an office and must get her suit dry cleaned everyday for $75.
Ulleksa [173]

Adrian will need to work 8 hours a day

3 0
3 years ago
Read 2 more answers
For the sequence 3, 8, 13, 18, 23, ….: (i) Find recursive and non-recursive formulas. (ii) Prove the non-recursive formula using
Aleksandr-060686 [28]

Answer:

Step-by-step explanation:

Given is the sequence 3, 8, 13, 18, 23, ….:

We find that this is a geometric sequence with each term added with 5 to the previous term

Hence recursive formula is a_n =a_{n-1} +5

Non recursive formula:

a_n =a_{n-1} +5=a_{n-2} +2(5)\\=a_{n-3} +3(5)-...\\=a_{n-(n-1)} +5(n-1)\\=a_1+(n-1)5\\=3+5n-5\\=5n-2

iii) Start with 3.

Add 5 and write as 2nd term

Take the resulting term and add 5 and mark as 3rd term

Repeat this m times.

7 0
3 years ago
If A = (0, 0) and B = (6, 3) what is the length of overline AB ?
Kaylis [27]

Answer:

A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

d = \sqrt{(x_B -x_A)^2 +(y_B -y_A)^2}

And replacing we got:

d = \sqrt{(6-0)^2 +(3-0)^2} = \sqrt{45}= 3\sqrt{5}

So then the length AB would be 3\sqrt{5}

Step-by-step explanation:

For this case we have the following two points:

A= (0,0) and B = (6,3)

We can find the length AB with the following formula:

d = \sqrt{(x_B -x_A)^2 +(y_B -y_A)^2}

And replacing we got:

d = \sqrt{(6-0)^2 +(3-0)^2} = \sqrt{45}= 3\sqrt{5}

So then the length AB would be 3\sqrt{5}

7 0
3 years ago
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