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BlackZzzverrR [31]
3 years ago
9

Which is the product of 5/18 and 6?

Mathematics
1 answer:
hoa [83]3 years ago
4 0
The answer to this question is B
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Consider a population with population proportion p, and a sample from the population with sample proportion pˆ. Which of the fol
Deffense [45]

According to CollegeBoard.org:

<u>Answer</u>: "To estimate the probability of observing a value as extreme as  pˆ  given  p."

<u>Explanation</u>: "The test statistic for a one-sample z-test is the distance, in units of standard deviations, between the statistic and the given parameter. From that distance, probabilities (a p-value) can be calculated and a claim can be assessed."

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3 years ago
How many hours will it take them to mow their lawn?
harkovskaia [24]

Answer:

C. 2

Step-by-step explanation:

h/6 + h/3 = 1

h/6 + 2h/6 = 1

3h/6 = 1

3h = 6

h = 2

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3 years ago
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Answer:

the answer is 8,000

Step-by-step explanation:

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3 years ago
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Translate the difference of five squared and n into symbols.
stira [4]

Answer:

5² - n  

Step-by-step explanation:

Five squared  = 5²

                     n =        n     Subtract n from 5²

                 Diff. = 5² - n

We indicate "taking the difference" by a "minus" sign, so all the other options are <em>wrong. </em>

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3 years ago
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The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili
Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

\lambda= 4.5

Formula:

P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}

a) No accidents occur in one week.

P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111

b) 5 or more accidents occur in a week.

P( x \geq 5) = 1-\displaystyle \sum P(x

c) One accident occurs today.

The mean number of accidents per day is given by

\lambda = \dfrac{4.5}{7} = 0.64

P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747

5 0
3 years ago
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