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3 years ago

Can someone please help me with this question

Mathematics

2 answers:

Paladinen [302]3 years ago

6 0

Answer

180 - x

Step-by-step explanation:

opposite angles of a quadrilateral inscribed in a circle are supplementary

lubasha [3.4K]3 years ago

3 0

Answer:

180-x !!!

Step-by-step explanation:

i had some time to think about it

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10m radius. What is the area of the circle? Round your answer to the nearest tenth.

Evgen [1.6K]

Answer:

Step-by-step explanation:

The area of a circle can be found using:

a=πr^2

We know that the radius is 10 meters. Therefore, we can substitute 10 in for r.

a=π*10^2

Evaluate the exponent

a=π*100

Multiply pi and 100

a=314.159265359

Round to the nearest tenth: there is a 5 in the hundreth place, which indicates we round up the 1 in the tenths place to a 2.

a=314.2

The area is 314.2 square meters, or choice D

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3 years ago

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How many solutions does this nonlinear system of equations have?

Arlecino [84]

Answer:

Step-by-step explanation:

One common point of the graphs means one solution.

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3 years ago

Which graph shows the solution to the following equation?<br><br> 2x-5/x^2 = -4

Romashka [77]

Answer:

THE THIRD ONE

Step-by-step explanation:

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3 years ago

(8x + 8)(x+3)<br><br> What is this answer

NemiM [27]

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8x^2+32x+24

Step-by-step explanation:

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3 years ago

Which equations and/or functions represent the graphed line? Select three options.

9966 [12]

Answer:

Point slope form : $y-3=\frac{1}{2}(x-2)$

Slope intercept form: $y=\frac{1}{2}(x)+2$

Standard form : $-x+2y=4$

Step-by-step explanation:

From the given graph it is clear that the line is passing through the points, (-4, 0), (-2, 1), (0, 2), and (2, 3).

If a line passes through two points $(x_1,y_1)$ and $(x_2,y_2)$ , then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Let as consider any two points of the line: (2, 3) and (0, 2).

The equation of line is

$y-3=\frac{2-3}{0-2}(x-2)$

$y-3=\frac{1}{2}(x-2)$

The point slope form of the line is $y-3=\frac{1}{2}(x-2)$ .

$y-3=\frac{1}{2}(x)-\frac{1}{2}(2)$

$y-3=\frac{1}{2}(x)-1$

Add 3 on both sides.

$y=\frac{1}{2}(x)-1+3$

$y=\frac{1}{2}(x)+2$

Therefore the slope intercept form of the line is $y=\frac{1}{2}(x)+2$ .

Multiply both sides by 2.

$2y=x+4$

$-x+2y=4$

Therefore, the standard form of the line is $-x+2y=4$ .

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4 years ago

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