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V125BC [204]
3 years ago
8

Find the slope of the line graphed below.

Mathematics
1 answer:
Law Incorporation [45]3 years ago
7 0

Answer:

8/5

Step-by-step explanation:

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WILL GIVE BRAINLIEST AND 30 POINTS!
Katena32 [7]

Answer:

2x\sqrt{10}-2x\sqrt 5

Step-by-step explanation:

\sqrt{5x} (\sqrt{8x^2}-2\sqrt{x})\\\mathrm{Multiply \: parentheses \: by \sqrt{5x}}\\=\sqrt{5x \times 8x^2}-2\sqrt{5x \times x}\\=x\sqrt {4\times 10 x}-2x\sqrt{5}\\=2x\sqrt{10}-2x\sqrt{5}

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3 years ago
A pair of parallel lines is cut by a transversal<br> What are the measures of the two marked angles?
krok68 [10]

Answer:

A 40 and 40

Step-by-step explanation: if two of the angles were cut by a transversal you would get A as an answer i think....

8 0
2 years ago
Express the improper fraction as a mixed number in simplest form 39/8
mestny [16]

32 7/8 would be the answer. All you have to do is find a number multiplied by & that gets you close enough to 39

4 0
3 years ago
Read 2 more answers
Waiting for other questions
Fudgin [204]

Answer:

A) 13

Step-by-step explanation:

If you recall the formula for finding a diagonal, or a^2 + B^2 = C^2, you will get 12^2 + 5^2 = C^2, if you solve that, you will get 13!

4 0
2 years ago
hello I need help with question 2 attached is the tables created in question one which I need to base question 2 off of. 2. Find
Vadim26 [7]

The given functions are:

\begin{gathered} f(x)=3x+2 \\ g(x)=\frac{x-2}{3} \end{gathered}

The domain is the set of all possible values that the independent variable (x) can take.

The range is the set of values that the function will take.

For these functions, the domain is all real numbers since they both will work with any positive or negative number (-∞,∞). Thus, the range is the same, all real numbers (-∞,∞).

But, for the purpose of the question let's analyze the interval you took for the table of values:

For f(x) function, you take x-values from -3 to 3, then the domain in this interval is [-3,3] and the range is the output values (f(x)), then the range is [-7,11].

For g(x) function, you take x-values from -7 to 11, then the domain in the interval is [-7,11] and the range (the g(x) values obtained) is [-3,3].

As can be noticed, in the interval the domain of the f(x) functions is the same as the range of the g(x) function, and the domain of the g(x) function is the same as the range of f(x) function. This happens because g(x) is the inverse function of f(x).

3 0
1 year ago
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