All categories

3 years ago

I need help on a equation −4a5⋅6a5

1 answer:

7 0

I don’t understand the equation but you can use Photomath to solve any equation you need to solve. It’s and app for free.

You might be interested in

Explain how to get the answer please

mart [117]

Answer:

y=8.50x+0.25

Step-by-step explanation:

She/he starts off with 8.50 and throughout the week she can earn 0.25 per joke. We don't know how many times a joke is made so it would be an x.

4 0

3 years ago

Read 2 more answers

Please help me fast <br> You don’t need to explain just send the answer

Andrej [43]

Answer:

70.5 it is the answer. I hope I am helpful please mark brainlist

4 0

2 years ago

Can you help me plz ?

Alexxx [7]

Given: 30 total days and there were 6 days with rain with a temperature below 70 degrees

To find the percentage, divide the part (6 days) by the whole (30 days) then multiply the quotient by 100.

(6 days / 30 days) x 100 = 20%

20% of the days in June had a temperature below 70 degrees and had rain.

7 0

2 years ago

Read 2 more answers

1.- What is 'a' for this hyperbola?

SpyIntel [72]

Answer:

The standard form of a hyperbola with vertices and foci on the x-axis:

$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1$

where:

center: (h, k)
vertices: (h+a, k) and (h-a,k)
Foci: (h+c, k) and (h-c, k) where the value of c is c² = a² + b²
Slopes of asymptotes: $\pm\left(\dfrac{b}{a}\right)$

The center of the given hyperbola is (0, 0), therefore:

$\implies \dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$

Therefore $(\pm a,0)$ are the vertices. From inspection of the graph, $a=2$ .

Choose two points on the asymptote with the positive slope:

(0, 0) and (4, 6)

Use the slope formula to find the slope:

$\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{6-0}{4-0}=\dfrac{3}{2}$

Use the <u>slopes of asymptotes</u> formula, compare with the slope found in part 2:

$\implies \dfrac{b}{a}=\dfrac{3}{2}$

Therefore, $b=3$

Substitute the found values of $a$ and $b$ into the equation from part 1:

$\implies \dfrac{x^2}{2^2}-\dfrac{y^2}{3^2}=1$

$\implies \dfrac{x^2}{4}-\dfrac{y^2}{9}=1$

4 0

1 year ago

Please help <br> u have to the Pythagorean Theorem

andriy [413]

Answer:

13.7

Step-by-step explanation:

$x^2 + 30^2 = 33^2$

$x^2 + 900 = 1089$

$x^2 = 189$

$x = \sqrt{189}$

$x = 13.7$

4 0

2 years ago

I need help on a equation −4a5⋅6a5​

I need help on a equation −4a5⋅6a5