12000
Just do
120000 divided by 10
p=7, I don't know if this is a question or not
Let X be a discrete binomial random variable.
Let p = 0.267 be the probability that a person does not cover his mouth when sneezing.
Let n = 18 be the number of independent tests.
Let x be the number of successes.
So, the probability that the 18 individuals, 8 do not cover their mouth after sneezing will be:
a) P (X = 8) = 18! / (8! * 10!) * ((0.267) ^ 8) * ((1-0.267) ^ (18-8)).
P (X = 8) = 0.0506.
b) The probability that between 18 individuals observed at random less than 6 does not cover their mouth is:
P (X = 5) + P (X = 4) + P (X = 3) + P (X = 2) + P (X = 1) + P (X = 0) = 0.6571.
c) If it was surprising, according to the previous calculation, the probability that less than 6 people out of 18 do not cover their mouths is 66%. Which means it's less likely that more than half of people will not cover their mouths when they sneeze.
Answer:
Step-by-step explanation:
First, distribute the 2 to the 3z and -6 within the parenthesis.
You know have 6z -12/5 + 6 = 10
Subtract 6 from both sides of the equation
6z -12/5 = 4
Multiply 5 on both sides of the equation
6z -12 = 20
Add 12 to both sides of the equation
6z = 32
Divide by 6 on both sides of the equation
z = 32/6
Simplify
z = 16/3
I hope that this helps! :)
