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olchik [2.2K]
3 years ago
5

Amira pulls a 3 pound wagon 4 feet. How much work has she done?

Mathematics
2 answers:
Alex787 [66]3 years ago
8 0

Answer:

12 ft-lbs is your answer

rjkz [21]3 years ago
3 0

12ft-lbs that she has done

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If a four-sided figure has four congruent sides, then it has four right angles. Prove this wrong
Mariulka [41]
A rhombus is a shape with four congruent sides but its angles are not congruent.
8 0
3 years ago
A Is a number that Is a multiple of two or more denominators.
34kurt
The answer to 1 is common multiple. And the answer to 2 is common denominator
3 0
4 years ago
Calculate the total area of the shaded region.
LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

7 0
2 years ago
Please help me thank you so much.
rewona [7]
Question 1:

Here's an interesting property of trapezoids:

Since this is a trapezoid, we know the following:
a+36 = 180
b+113 = 180

We only want to solve for a

a + 36 = 180

Subtract both sides by 36

a = 144

Your answer is the second choice.

Question 2:

Since LM is the midsegment, the length of LM is the average of the length of AB and DC.

(AB + DC) / 2 = LM

(46 + 125) / 2

= 171 / 2

= 85.5

The last choice is your answer.

Have an awesome day! :)
4 0
3 years ago
At a local company, the ages of all new employees hired during the last 10 years are normally distributed. The mean age is 38 ye
N76 [4]

Answer:

P = 21%

Step-by-step explanation:

We look for the percentage of employees who are not more than 30 years old.

This is:

P = \frac{x}{n} *100\%

Where x is the number of new employees who are not over 30 years old and n is the total number of new employees.

We do not know the value of x or n. However, the probability of randomly selecting an employee that is not more than 30 years old is equal to P = \frac{x}{n}

Then we can solve this problem by looking for the probability that a new employee is not more than 30 years old.

This is:

P(X< 30)

Then we find the z-score

Z = \frac{X - \mu}{\sigma}

We know that:

μ = 38 years

\sigma = 10 years

So

Z = -0.8

Then

P (X

By symmetry of the distribution

P(Z0.8)

Looking in the normal standard tables

P(Z>0.8)=0.211

Finally P = 21%

3 0
3 years ago
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