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2 years ago

Can someone help me?2b²+17b+21Thanks

Mathematics

2 answers:

vladimir1956 [14]2 years ago

6 0

Answer:

(2b+3) (b+7)

Step-by-step explanation:

2b²+17b+21

2b²+14b+3b+21

2b(b+7) + 3(b+7)

(2b+3) (b+7)

sveticcg [70]2 years ago

5 0

Answer:

roots are -3 and -14

Step-by-step explanation:

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2 years ago

Jaden is flying a kite with an angle of elevation of 33 degrees. If Jaden lets out 275 feet of string, how high above the ground

pshichka [43]

Answer:

149.8 feet

Step-by-step explanation:

θ = Angle of elevation = 33°

The length of string Jaden lets out = Hypotenuse = 275 feet.

How high above the ground that the kite is flying = Opposite Side.

We are solving this question using the Trigonometric function of Sine

Sin θ = Opposite Side/Hypotenuse

Sin 33 = Opposite/275 feet

Cross Multiply

Sin 33 × 275 feet = Opposite

Opposite side(Height ) = 149.77573463 feet

Approximately to the nearest tenth = 149.8 feet

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2 years ago

If xy plane line is y=2x+4, y=x-5 will intercept at which point?

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2 years ago

What is the nth term rule of the quadratic sequence below?

Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

Given sequence:

6, 20, 40, 66, 98, 136, ...

Calculate the first differences between the terms:

$6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136$

As the first differences are not the same, calculate the second differences:

$14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38$

As the second differences are the same, the sequence is quadratic and will contain an n² term.

The coefficient of the n² term is half of the second difference.

Therefore, the n² term is: 3n²

Compare 3n² with the given sequence:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

The second operations are different, therefore calculate the differences between the second operations:

$3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18$

As the differences are the same, we need to add 5n as the second operation:

$\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2 &-2 & -2 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}$

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0

1 year ago

Can someone help me?2b²+17b+21Thanks​

Can someone help me?2b²+17b+21Thanks