Ask question

Ask question

All categories

zloy xaker [14]

3 years ago

7

The school cafeteria served 2,680 cups of milk in March and 1,480 cups of milk in April. How many quarts of milk did the cafeter

ia serve in those two months?

1 answer:

nignag [31]3 years ago

8 0

Answer:

<h2 />

Step-by-step explanation:

ghh $bb\sqrt{x}$ btw go check out fidgetshopbutterflys on and follow on tiktok

You might be interested in

Based on the line plot, how many batteries lasted more than 5 1/2 hours? *

babunello [35]

Answer:

5 batteries.

Explanation:

"How many batteries lasted more than 5 1/2 hours?" which means it's counting not only 5 1/2, but 5 3/4 and 6 1/4

3 0

3 years ago

Read 2 more answers

Concept maps work because they _______.

AnnZ [28]

Showing the relationships among concepts.

7 0

3 years ago

Read 2 more answers

The crew on a fishing boat caught 4 fish that weighed a total of 1,092 pound. The tarpon weighed twice as much as the amberjack

Savatey [412]

ddddd

Let T be the weight of Tarpon

Let A be the weight of amberjack

Let W be the weight of white marlin

Let TU be the weight of Tuna

The crew on a fishing boat caught 4 fish that weighed a total of 1,092 pound.

Total weight = 1092

T + A + W + TU = 1092

The tarpon weighed twice as much as the amberjack

T= 2 A

the white marlin weighed twice as much as the tarpon.

W = 2 T

We know T is 2A so W = 2(2A) = 4 A, W = 4A

The weight of the tuna was 5 times the weight of the Amber jack.

TU = 5A

T = 2A , W = 4A , TU = 5A

Replace it in our equation

T + A + W + TU = 1092

2A + A + 4A + 5A = 1092

12A = 1092

Divide both sides by 12

A = 91

the weight of amberjack = 91 pounds

the weight of white marlin = 4A = 4(91) = 364 pounds

the weight of Tarpon = 2A = 2(91) = 182 pounds

the weight of Tuna= 5A = 5(91)=455 pounds

7 0

2 years ago

The length of a rectangle is 5 more than twice the width. the perimeter is 130. what is the area?

vekshin1

<span>L the length W the width

The length of a rectangle is 5 more than twice the width</span>
L = 5+ 2W

<span>the perimeter is equal the sum of sides =130
</span>
L+L+W+W =130

by subtitution we replace L by <span>L = 5+ 2W

</span>5+ 2W+<span>5+ 2W +W+W = 130
</span>
6W= 120

w= 20 <span>L = 5+ 2W= 5+ 40=45</span>

7 0

2 years ago

What is the distance from the point (a, −b, −4) to the origin?

laiz [17]

Answer:

$\sqrt{a^2+b^2+16}$

Step-by-step explanation:

The distance (d) between two points in 3 dimensions is ...

d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²)

Then the distance between (a, -b, -4) and (0, 0, 0) is ...

d = √((a -0)² +(-b -0)² +(-4 -0)²)

= √(a² +b² +16)

6 0

3 years ago