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3 years ago

ANSWERRRR IF UR COOL!! Plssss ILL MARK BRAINLEST Ty!!! So much ilyyyyyyy

Mathematics

2 answers:

patriot [66]3 years ago

4 0

Answer number 3. Since it's obvious in the picture.

frez [133]3 years ago

3 0

Answer:

-2 and -1

Step-by-step explanation:

Thus ; from -1 we will move to -1.5,-2 moving to -2.5 and continuous

You might be interested in

Find the area of the irregularly-shaped hexagon below

Ber [7]

let each box length be 1

for white triangle

area = ½bh

=½(4)(2)

for orange triangle

area=½(2)(3)

for blue marked boxes

each of the box

area=l²

=(1)²

there are 16 boxes

so the total area will be 16

total area of the hexagon = 4+3+16

=23 square units

7 0

3 years ago

Read 2 more answers

Help scroll through the pics

zhenek [66]

Answer:

there is no pics any problem?

3 0

3 years ago

The gcf of 30 and N is 15. What is N?

JulijaS [17]

Answer:

n=45

Step-by-step explanation:

30=1, 2, 3, 5, 6, 10, 15 and 30.

45=1, 3, 5, 9, 15 and 45.

-hope it helps

6 0

2 years ago

I Need help please What is the value of a? -2(a-8) 6a=36

pishuonlain [190]

I think the value of a is 6 because if 6a=36 then 36 divided by 6 is 6

8 0

3 years ago

Assume that the Poisson distribution applies to the number of births at a particular hospital during a randomly selected day. As

kakasveta [241]

Answer:

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Assume that the mean number of births per day at this hospital is 13.4224.

This means that $\mu = 13.4224$

Find the probability that in a day, there will be at least 1 birth.

This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13.4224}*13.4224^{0}}{(0)!} = 0.0000015$

Then

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000015 = 0.9999985
$

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

7 0

3 years ago