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Maurinko [17]
3 years ago
9

A large spherical structure has a 37.5-foot radius. The sphere is covered with panels. If each panel has an area of about 49 ft2

, approximately how many panels would be needed to cover the entire sphere?
360

940

17,660

310,000
Mathematics
2 answers:
Citrus2011 [14]3 years ago
4 0

Answer:

Option (1)

Step-by-step explanation:

Radius of the spherical structure = 37.5 feet

Surface area of each panel = 49 square feet

Sphere is covered with panels.

Therefore, area of the panels needed = \frac{\text{Total surface area of the sphere}}{\text{Area of one panel}}

Surface area of the sphere = 4πr²

Here 'r' = radius of the sphere

For a sphere having radius 'r' = 37.5 feet,

Surface area of the sphere = 4π(37.5)²

                                             = 17671.5 feet²

Number of panels required to cover the sphere = \frac{17671.5}{49}

                                                                                = 360

Therefore, Option (1) will be the answer.

vodomira [7]3 years ago
3 0

Answer:

360

Step-by-step explanation:

got it right on edge

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Answer:

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x = 0 ---> f(x) = 0

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6 0
3 years ago
An alloy consists of nickel, zinc, and copper in the ratio 2:7:9. How many pounds of nickel have to be used to create alloy that
Cloud [144]

ANSWER

Find out the  how many pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.

To proof

As given

An alloy consists of nickel, zinc, and copper in the ratio 2:7:9.

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assuming one part be x.

thus

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