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Maurinko [17]
3 years ago
9

A large spherical structure has a 37.5-foot radius. The sphere is covered with panels. If each panel has an area of about 49 ft2

, approximately how many panels would be needed to cover the entire sphere?
360

940

17,660

310,000
Mathematics
2 answers:
Citrus2011 [14]3 years ago
4 0

Answer:

Option (1)

Step-by-step explanation:

Radius of the spherical structure = 37.5 feet

Surface area of each panel = 49 square feet

Sphere is covered with panels.

Therefore, area of the panels needed = \frac{\text{Total surface area of the sphere}}{\text{Area of one panel}}

Surface area of the sphere = 4πr²

Here 'r' = radius of the sphere

For a sphere having radius 'r' = 37.5 feet,

Surface area of the sphere = 4π(37.5)²

                                             = 17671.5 feet²

Number of panels required to cover the sphere = \frac{17671.5}{49}

                                                                                = 360

Therefore, Option (1) will be the answer.

vodomira [7]3 years ago
3 0

Answer:

360

Step-by-step explanation:

got it right on edge

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Answer:

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Step-by-step explanation:

From the image we can see that the only congruent relation ∠FJH has is with ∠BJA which is due to these angles being vertically opposite

So, ∠FJH and ∠BJA are vertically opposite and hence, congruent. We can say that ∠FJH ≅ ∠BJA

4 0
3 years ago
2. CHEMISTRY How many liters of 15% acid and
Wewaii [24]

Answer:  

<h3>         26²/₃ liters of 15% acid and 13¹/₃ liters of 33% acid</h3>

Step-by-step explanation:

Concentration            Amount of             Amount

of Solution                   Solution (L)             of Acid

    15%                                x                         0.15x

    33%                               y                         0.33y

    21%                              40                      0.21•40      

       

x + y = 40    ⇒  x = 40 - y

0.15x + 0.33y = 0.21•40

0.15(40 - y) + 0.33y = 0.21•40

6 - 0.15y + 0.33y = 8.4

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        y = 13¹/₃

x = 40 -  13¹/₃ = 26²/₃

8 0
3 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

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Answer:

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Step-by-step explanation:

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