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Shkiper50 [21]
2 years ago
13

How to I put x>-2.5 on a number line?

Mathematics
1 answer:
AysviL [449]2 years ago
4 0

Answer:

Open circle. Points right

Step-by-step explanation:

The reason for it is because this symbol > represents greater than when it comes to inequalities. When it is an open circle that means that you are not including the number. So that also means that the -2.5 is not included to the inequality equation but it can be any other number other than that number.

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3/4^2 + 1^2 = x2<br><br> solve for x with work shown! pls help!
photoshop1234 [79]

Answer:

X=19/32

Step-by-step explanation:

3/4^2+1^2=2*x

3/4^2+1=2x

3+(4^2)/4^2=2x

3+16/4^2=2x

19/4^2=2x

19/(2^2)^2=2x

19=16(2x)

19=16*2x

32x=19

32x/32=19/32

x=19/32

This took alot of time goodluck!

8 0
2 years ago
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Setler [38]
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6 0
2 years ago
What is the equation of the line that passes through the point (-8,2) and had an undefined slope
Basile [38]

Answer:

-8..hope it helps you

Step-by-step explanation:

x=-8..Y=2

5 0
2 years ago
How do you solve 10(z-2)=1+4
tamaranim1 [39]

I'm assuming you want us to solve for the unknown variable z

10(z-2)=1+4

Combine like terms on the right side

10(z-2)=5

Use the distributive property on the left side

10z-20=5

Add both sides by 20 to cancel out the "-20" on the left side

10z=25

Divide both sides by 10

z=2.5

That is the value of the known variable, z, in this equation. Let me know if you need any clarifications, thanks!

~ Padoru

6 0
2 years ago
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Listed below are amounts​ (in millions of​ dollars) collected from parking meters by a security service company and other compan
Vikentia [17]

Answer:

CV=\frac{0.1252}{1.57}=0.07975

CV=\frac{0.1317}{1.72}=0.07657

The relative variability is almost equal in both samples a slight greater variability can be noticed in the first sample.

Step-by-step explanation:

The coefficient of variation of a sample is defined as the ratio between the mean standard deviation and the sample mean. And it represents the percentage relation of the variation of the data with respect to the average.

CV=\frac{S}{\bar X}

In the case of the first sample you have:

CV=\frac{0.1252}{1.57}=0.07975

In the case of the second sample you have:

CV=\frac{0.1317}{1.72}=0.07657

The relative variability is almost equal in both samples a slight greater variability can be noticed in the first sample.

6 0
3 years ago
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