We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0

3 years ago

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A hollow toy, with the dimensions shown in the figure, is to be stuffed with rigid foam. What is the maximum amount of foam that

Fudgin [204]

Option B: 67.02 cubic inches

<h2>Given that:</h2>

The diagram consists of two parts:

First a cone on the top with 12 inches height and 4 inches diameter.

Second a semi sphere with diameter of 4 inches.

<h2>Calculations:</h2>

The amount of foams that can be stuffed with foam is total volume of both the containers.

Volume of the given cone of 12 inches height and 4 inches diameter can be given as:

$\dfrac{1}{3} \times \pi \times 2^2 \times 12\\= 50.265 \: \rm inch ^3$

Volume of the semi sphere of 4 inches diameter can be given as:

$\dfrac{2}{3} \pi \times 2^3\\= 16.755 \: \rm inch^3$

Thus total volume is 50.265 + 16.755 = 67.02 cubic inches.

Thus option B : 67.02 cubic inches is the needed volume.

Learn more here:

brainly.com/question/1315822

7 0

2 years ago

Draw a graph of the rose curve.<br><br> r = 4 cos 2θ, 0 ≤ θ ≤ 2π

alukav5142 [94]

See the attachment below gor graph
hope that helps

3 0

3 years ago

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