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True [87]
3 years ago
13

Is this a function or not a function?

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0
No it is not a function
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Please answer the question in the image.
solniwko [45]

First find x:

3x + 41 + x + x-8 + 2 = 100

Simplify :

5x + 35 = 100

Subtract 35 from both sides:

5x = 65

Divide both sides by 5:

X = 13

Total British stamps = x + x-8 = 13 + 13-8 = 18

Probability of being British = 18/100 = 9/50 as a fraction.

5 0
3 years ago
Name the angle relationship
Mice21 [21]

Answer:

Alternate interior

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Write a quadratic function in standard form with a leading coefficient of 1 for the given set of zeros. 7 and 4
Viefleur [7K]

We are given : Zeros x=7 and x=4 and leading coefficent 1.

In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.

For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).

So, we need to multiply (x-7) and (x-4) by foil method.

We get

(x-7)(x-4) = x*x + x* -4 -7*x -7*-4

x^2 -4x -7x +28.

Combining like terms, we get

-4x-7x = -11x

x^2 -4x -7x +28 = x^2 -11x +28.

Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.

We get

1(x^2 -11x +28) = x^2 -11x +28.

Therefore, the required quadratic function in standard form is x^2 -11x +28.


6 0
3 years ago
Whats the exponential form for -1/6×-1/6×-1/6×-1/6=?
KengaRu [80]
I hope this helps you

4 0
3 years ago
Read 2 more answers
I do not understand how to work out this question please help
enot [183]

a) To find the missing side length on triangle A, we can use the Pythagorean theorem.

a^2 + 12^2 = 13^2

a^2 + 144 = 169

a^2 = 25

a = 5 cm

5 and 12 = 5 and 12

b) The two triangles are congruent because they have two side lengths in common. If at least two side lengths are the same on two triangles, then they are congruent. In addition, these triangles have one angle in common as well.

Hope this helps!! :)

8 0
3 years ago
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