Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
Answer:
4x(squared)-36
Step-by-step explanation:
=(2x+−6)(2x+6)
=(2x)(2x)+(2x)(6)+(−6)(2x)+(−6)(6)
=4x^2+12x−12x−36
=4x^2 −36
Answer:
its letter c so 80
Step-by-step explanation:
I hope this help